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y = ax^2 + c where a and c are constants and a is not 0.

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Q: Equation of parabola that has y as axis of symmetry?
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How do you find the y-coordinate vertex of a parabola?

Once you calculate the X coordinate using the axis of symmetry (X=-b/2a), you plug that value in for all of the X's in the equation of the parabola. You then solve the equation for the value of Y.


What is the standard equation for vertex at origin opens down 1 and 76 units between the vertex and focus?

Since the vertex is at the origin and the parabola opens downward, the equation of the parabola is x2 = 4py, where p < 0, and the axis of symmetry is the y-axis. So the focus is at y-axis at (0, p) and the directrix equation is y = -p. Now, what do you mean with 1 and 76 units? 1.76 units? If the distance of the vertex and the focus is 1.76 units, then p = -1.76, thus 4p = -7.04, then the equation of the parabola is x2 = -7.04y.


What do you know about a function that is made up of ordered pairs in such a way that the same y-value appears in a correspondence with two different x-values?

For example, y = ax2 + bx + c (the equation of a parabola). Every parabola has an axis of symmetry and the graph to either side of the axis of symmetry is a mirror image of the other side. It means that if we know a point on one side of the parabola, we can find its symmetric point to the other side, based on the axis of symmetry. Those symmetric points have opposite x-coordinate values, and the same y-coordinate value. The vertex only is a single point which lies on the axis of symmetry.


What is the line of symmetry for the parabola whose equation is y x2 - 12x 7?

y=x2-12x+7


Where a parabola crosses the x-axis?

These are called the zeros of the equation. They are the places where y=0

Related questions

What is the line of symmetry for the parabola whose equation is y -x2 x 3?

Did you mean a parabola with equation y=3x^2? The line of symmetry is x=0 or the y-axis.


What is an equation of the axis of symmetry of the parabola represented by y equals -x2 plus 6x-4?

Line of symmetry: x = 3


An equation of a parabola that has x equals 2 as its axis of symmetry is?

How about y = (x - 2)2 = x2 - 4x + 4 ? That is the equation of a parabola whose axis of symmetry is the vertical line, x = 2. Its vertex is located at the point (2, 0).


How do you find the y-coordinate vertex of a parabola?

Once you calculate the X coordinate using the axis of symmetry (X=-b/2a), you plug that value in for all of the X's in the equation of the parabola. You then solve the equation for the value of Y.


Where is the line of symmety located on a parabola?

The line of symmetry located on a parabola is right down the center. A parabola is a U shape. Depending on the direction of the parabola it either has a x axis of symmetry or y axis of symmetry. You should have two equal sides of the parabola.


What is the axis of symmetry for the parabola with vertex (-2 -4) and directrix y 1?

The axis of symmetry is x = -2.


Where is the axis of symmetry of a parabola located?

Parallel to the y-axis, going through the highest/lowest point of the parabola (if the parabola is negative/positive, respectively).


Where does the parabola cross the x axis?

Set y = 0 and solve for x, with a parabola you should get one, two, or no x-axis crossings, it depends on the equation and the location on the x-y axis of the parabola.


What is the standard equation for vertex at origin opens down 1 and 76 units between the vertex and focus?

Since the vertex is at the origin and the parabola opens downward, the equation of the parabola is x2 = 4py, where p < 0, and the axis of symmetry is the y-axis. So the focus is at y-axis at (0, p) and the directrix equation is y = -p. Now, what do you mean with 1 and 76 units? 1.76 units? If the distance of the vertex and the focus is 1.76 units, then p = -1.76, thus 4p = -7.04, then the equation of the parabola is x2 = -7.04y.


Can there be multiple y-interecepts?

Yes. think of a parabola that curves around the y-axis. an equation like x = square root of (y2 - 9) simply switch the x's and y's in the equation and your parabola opens up around the y-axis and the x-axis respectively


What do you know about a function that is made up of ordered pairs in such a way that the same y-value appears in a correspondence with two different x-values?

For example, y = ax2 + bx + c (the equation of a parabola). Every parabola has an axis of symmetry and the graph to either side of the axis of symmetry is a mirror image of the other side. It means that if we know a point on one side of the parabola, we can find its symmetric point to the other side, based on the axis of symmetry. Those symmetric points have opposite x-coordinate values, and the same y-coordinate value. The vertex only is a single point which lies on the axis of symmetry.


The equation for the axis of symmetry is?

Your equation must be in y=ax^2+bx+c form Then the equation is x= -b/2a That is how you find the axis of symmetry