The conjugate of 6 + i is 6 - i.
the conjugate 7-2i
Oh, isn't that just a happy little question? The complex conjugate of a real number like 8 is just 8 itself because there is no imaginary part to change. Just like how every tree needs its roots, every real number needs its complex conjugate to stay balanced and harmonious. Just remember, there are no mistakes, only happy little accidents in math!
How about "-i" since "i" is just "0 + i" so the conjugate should be "0 - i" or "-i"
semi conjugate diameter of ellipse
A conjugate (in the context of math) is, simply put, two numbersseparatedby a sign, in which the sign changes.Example:The conjugate of a+b is a-b. Thepositivebecame negative.For your problem (your sign is missing, so I listed two possibilities):The conjugate of 11+17i is 11-17iThe conjugate of 11-17i is 11+17i
The conjugate acid of ClO- is HClO. The conjugate acid of HClO is ClO2. The conjugate acid of HCI is H2Cl. The conjugate acid of Cl- is HCl. The conjugate acid of ClO is HClO2.
The conjugate base and conjugate acid for HS04 is: Conjugate acid is H2SO4 Conjugate base is SO42
"Conjugate" usually means that in one of two parts, the sign is changed - as in a complex conjugate. If the second part is missing, the conjugate is the same as the original number - in this case, 100.
The conjugate acid of NO2- is HNO2 (nitrous acid).
The conjugate acid of LiOH is considered Li+.
The conjugate acid of H2O is H3O+ (hydronium ion). When an acid donates a proton, it forms its conjugate base, and when a base accepts a proton, it forms its conjugate acid.
The conjugate of 6 + i is 6 - i.
It depends on what the denominator was to start with: a surd or irrational or a complex number. You need to find the conjugate and multiply the numerator by this conjugate as well as the denominator by the conjugate. Since multiplication is by [conjugate over conjugate], which equals 1, the value is not affected. If a and b are rational numbers, then conjugate of sqrt(b) = sqrt(b) conjugate of a + sqrt(b) = a - sqrt(b), and conjugate of a + ib = a - ib where i is the imaginary square root of -1.
The conjugate base of NH3 is NH2-, formed by removing a proton (H+) from NH3.
The conjugate base of HSO3- is SO32-.
the conjugate 7-2i