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You could just pull out the half: it will be (1/2) cos squared x.
Yes. Except where sin x = 0, because then you would be dividing by zero so the quotient is undefined.
One solution. (cos x)2 - 2cos x = 3 Factor: (cos x - 3)(cos x + 1)= 0 cos x = {-1, 3} Solve: For cos x = -1, x = 180 deg No solution for cos x = 3
The deriviative of sin2 x + cos2 x is 2 cos x - 2 sin x
No, (sinx)^2 + (cosx)^2=1 is though