To factor a^4 - b^4 completely, you can use the formula for the difference of squares, which states that a^2 - b^2 = (a + b)(a - b). In this case, a^4 - b^4 is a difference of squares twice: (a^2)^2 - (b^2)^2. So, you can factor it as (a^2 + b^2)(a^2 - b^2). Then, factor a^2 - b^2 further using the difference of squares formula to get (a^2 + b^2)(a + b)(a - b), which is the complete factorization of a^4 - b^4.
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a5+b5 = (a+b) (a4-a3b+a2b2-ab3+b4)
Usually simple substitutions enable such expressions to be seen as quadratic expressions. The substitutions x = a2 and y = b2 give a4 + b4 - 7a2b2 = x2 - 7xy + y2 which does not have any rational factors. Consequently, the quartic in a and b does not have rational factors.
(a^2 - b)(a^2 + b)(a^4 + b^2)
B4 but you sustain the A4 longer
Expand 4ab3 (a2b2-a-1)
The GCF is 1.
( a2 ) ( a2+1 )
(a^2 + 8b)(a^2 - 5b)
6 cells. They are A1, A2, A3, B1, B2 and B3.
Yes, B paper is bigger than A paper, for instance the average A4 is 21cm x 29.7cm, however B4 is 25cm x 35.3cm
Because of the way this is written, there are two possibilities in simplifying. Choose the one that applies:a4 - ab4 = a(a3 - b4); here, only the 'b' term is raised in the second term, so a1 is the only thing we can take out.a4 - (ab)4 - a4(1 - b4). Because a4 is a part of both terms, it can be removed from both as well.