false
Assuming that you mean not (p or q) if and only if P ~(PVQ)--> P so now construct a truth table, (just place it vertical since i cannot place it vertical through here.) P True True False False Q True False True False (PVQ) True True True False ~(PVQ) False False False True ~(PVQ)-->P True True True False if it's ~(P^Q) -->P then it's, P True True False False Q True False True False (P^Q) True False False False ~(P^Q) False True True True ~(P^Q)-->P True True False False
false
It is false.
False because every quadrilateral is a four sided shape
inversion is effected by a series of obversion and conversion
Conversion, obversion, contraposition
Conversion, obversion, contraposition
Conversion, obversion, contraposition
False
False
false
False
false.
True AND False OR True evaluates to True. IT seems like it does not matter which is evaluated first as: (True AND False) OR True = False OR True = True True AND (False OR True) = True AND True = True But, it does matter as with False AND False OR True: (False AND False) OR True = False OR True = True False AND (False OR True) = False AND True = False and True OR False AND False: (True OR False) AND False = True AND False = False True OR (False AND False) = True OR False = True Evaluated left to right gives a different answer if the operators are reversed (as can be seen above), so AND and OR need an order of evaluation. AND can be replaced by multiply, OR by add, and BODMAS says multiply is evaluated before add; thus AND should be evaluated before OR - the C programming language follows this convention. This makes the original question: True AND False OR True = (True AND False) OR True = False OR True = True
False False False FalseFalse
false!!!!!!