Consider a system of linear equations . Let be its coefficient matrix. elementary row operation.
(i) R(i, j): Interchange of the ith and jth row.
(ii) R(ci): Multiplying the ith row by a non-zero scalar c.
(iii) R(i, cj): Adding c times the jth row to the ith row.
It is clear that performing elementary row operations on the matrix (or on the equations themselves) does not affect the solutions. Two matrices and are said to be row equivalent if and only if one of them can be obtained from the other by performing a sequence of elementary row operations. A matrix is said to be in row echelon form the following conditions are satisfied:
(i) The number of first consecutive zerosincreases down the rows.
(ii) The first non-zero element in each row is 1.
The process of performing a sequence of elementary row operations on a system of equations so that the coefficient matrix reduces to row echelon form is called Gauss elimination. When a system of linear equations is transformed using elementary row operations so the coefficient matrix is in row echelon form, the solution is easily obtained by back substitution.
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Solve the following systems of simultaneous linear equations using Gauss elimination method and Gauss-Seidel Method 2x1+3x2+7x3 = 12 -----(1) x1-4x2+5x3 = 2 -----(2) 4x1+5x2-12x3= -3 ----(3) Answer: I'm not here to answer your university/college assignment questions. Please refer to the related question below and use the algorithm, which you should have in your notes anyway, to do the work yourself.
He proved the "fundamental theorem of algebra" and developed a method of minimizing statistical error called "the method of least squares" which is still used today.
It will solve the solution "exactly", but will take a very very long time for large matrices. Gauss Jordan method will require O(n^3) multiplication/divisions and O(n^3) additions and subtractions. Gauss seidel in reality you may not know when you have reached a solution. So, you may have to define the difference between succesive iterations as a tolerance for error. But, most of the time GS is much prefured in cases of large matrices.
Dorothea Benze and Gebhard Dietrich Gauss.
How many A/cm is equal to 1 Gauss