It is an algebraic expression for a measure of distance, in yards, where the unknown quantity is represented by h.
1 yd = 36 in 6 yd 5 in - 2 yd 7 in = (5 + 1) yd 5 in - 2 yd 7 in = 5 yd (36 + 5) in - 2 yd 7 in = (5-2) yd (36 + 5 - 7) in = 3 yd 34 in.
The diagonal of a rectangle with the length of 30 yd and the width of 30 yd is approximately 42.43 yd
5 yd x 3 = 15 yd
To find the volume of a square pyramid, we use the formula ( V = \frac{1}{3} \times \text{Base Area} \times \text{Height} ). The base area of the square is ( 54 , \text{yd} \times 54 , \text{yd} = 2916 , \text{yd}^2 ). To find the height, we can use the Pythagorean theorem: ( h = \sqrt{45^2 - (27)^2} = \sqrt{2025 - 729} = \sqrt{1296} = 36 , \text{yd} ). Therefore, the volume is ( V = \frac{1}{3} \times 2916 \times 36 = 34992 , \text{yd}^3 ).
2 yd = 72 in.
it is 9x7 and yd x yd so 63 and yd squared = 63 square yds.
3 yd = 274.32 cm3 yd = 274.32 cm3 yd = 274.32 cm3 yd = 274.32 cm3 yd = 274.32 cm3 yd = 274.32 cm
1 yd = 36 in 6 yd 5 in - 2 yd 7 in = (5 + 1) yd 5 in - 2 yd 7 in = 5 yd (36 + 5) in - 2 yd 7 in = (5-2) yd (36 + 5 - 7) in = 3 yd 34 in.
I think that it's 4472 yd/mi, but I'm not quite sure.
The diagonal of a rectangle with the length of 30 yd and the width of 30 yd is approximately 42.43 yd
5 yd x 3 = 15 yd
1 m = 1.094 yd 100 m * (1.094 yd/m) = 109.4 yd 109.4 yd / 10.6 s = 10.3208 yd/s 100 yd / (10.3208 yd/s) = 9.6892 s
174 sq. yards
2 yd = 72 in.
yards
6 ft / 3 ft/yd = 2 yd
64.8 square feet 36 in = 1 yd 1 cu yd = 1 sq yd x 1 yd 1 yd = 3 ft 1 sq yd = 1 yd x 1 yd = 3 ft x 3 ft = 9 sq ft volume = area x thickness ⇒ area = volume ÷ thickness = 1 sq yd x 1 yd ÷ 5 in = 1 sq yd x 1 yd ÷ (5 ÷ 36) yd = 7.2 sq yd = 7.2 x 9 sq ft = 64.8 sq ft