It is an algebraic expression for a measure of distance, in yards, where the unknown quantity is represented by h.
No, you cannot construct a triangle with side lengths 2 yd, 9 yd, and 10 yd. This is because the sum of the lengths of the two shorter sides (2 yd + 9 yd = 11 yd) must be greater than the length of the longest side (10 yd) to satisfy the triangle inequality theorem. Since 11 yd is greater than 10 yd, these lengths do not form a triangle.
1 yd = 36 in 6 yd 5 in - 2 yd 7 in = (5 + 1) yd 5 in - 2 yd 7 in = 5 yd (36 + 5) in - 2 yd 7 in = (5-2) yd (36 + 5 - 7) in = 3 yd 34 in.
The diagonal of a rectangle with the length of 30 yd and the width of 30 yd is approximately 42.43 yd
To find the volume of a square pyramid, we use the formula ( V = \frac{1}{3} \times \text{Base Area} \times \text{Height} ). The base area of the square is ( 54 , \text{yd} \times 54 , \text{yd} = 2916 , \text{yd}^2 ). To find the height, we can use the Pythagorean theorem: ( h = \sqrt{45^2 - (27)^2} = \sqrt{2025 - 729} = \sqrt{1296} = 36 , \text{yd} ). Therefore, the volume is ( V = \frac{1}{3} \times 2916 \times 36 = 34992 , \text{yd}^3 ).
5 yd x 3 = 15 yd
it is 9x7 and yd x yd so 63 and yd squared = 63 square yds.
3 yd = 274.32 cm3 yd = 274.32 cm3 yd = 274.32 cm3 yd = 274.32 cm3 yd = 274.32 cm3 yd = 274.32 cm
No, you cannot construct a triangle with side lengths 2 yd, 9 yd, and 10 yd. This is because the sum of the lengths of the two shorter sides (2 yd + 9 yd = 11 yd) must be greater than the length of the longest side (10 yd) to satisfy the triangle inequality theorem. Since 11 yd is greater than 10 yd, these lengths do not form a triangle.
I think that it's 4472 yd/mi, but I'm not quite sure.
1 yd = 36 in 6 yd 5 in - 2 yd 7 in = (5 + 1) yd 5 in - 2 yd 7 in = 5 yd (36 + 5) in - 2 yd 7 in = (5-2) yd (36 + 5 - 7) in = 3 yd 34 in.
The diagonal of a rectangle with the length of 30 yd and the width of 30 yd is approximately 42.43 yd
To find the volume of a square pyramid, we use the formula ( V = \frac{1}{3} \times \text{Base Area} \times \text{Height} ). The base area of the square is ( 54 , \text{yd} \times 54 , \text{yd} = 2916 , \text{yd}^2 ). To find the height, we can use the Pythagorean theorem: ( h = \sqrt{45^2 - (27)^2} = \sqrt{2025 - 729} = \sqrt{1296} = 36 , \text{yd} ). Therefore, the volume is ( V = \frac{1}{3} \times 2916 \times 36 = 34992 , \text{yd}^3 ).
5 yd x 3 = 15 yd
1 m = 1.094 yd 100 m * (1.094 yd/m) = 109.4 yd 109.4 yd / 10.6 s = 10.3208 yd/s 100 yd / (10.3208 yd/s) = 9.6892 s
174 sq. yards
64.8 square feet 36 in = 1 yd 1 cu yd = 1 sq yd x 1 yd 1 yd = 3 ft 1 sq yd = 1 yd x 1 yd = 3 ft x 3 ft = 9 sq ft volume = area x thickness ⇒ area = volume ÷ thickness = 1 sq yd x 1 yd ÷ 5 in = 1 sq yd x 1 yd ÷ (5 ÷ 36) yd = 7.2 sq yd = 7.2 x 9 sq ft = 64.8 sq ft
yards