The integral of f'(x) = 1 is f(x) = x + c
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Using chain rule:integral of cos2x dx= 1/2 * sin2x + C
Integral( sin(2x)dx) = -(cos(2x)/2) + C
∫ 1/cos(x) dx = ln(sec(x) + tan(x)) + C C is the constant of integration.
∫ d/dx f(x) dx = f(x) + C C is the constant of integration.
x5lnx?d/dx (uv)=u*dv/dx+v*du/dxd/dx (x5lnx)=x5*[d/dx(lnx)]+lnx*[d/dx(x5)]-The derivative of lnx is:d/dx(lnu)=(1/u)*[d/dx(u)]d/dx(lnx)=(1/x)*[d/dx(x)]d/dx(lnx)=(1/x)*[1]d/dx(lnx)=(1/x)-The derivative of x5 is:d/dx (xn)=nxn-1d/dx (x5)=5x5-1d/dx (x5)=5x4d/dx (x5lnx)=x5*[1/x]+lnx*[5x4]d/dx (x5lnx)=[x5/x]+5x4lnxd/dx (x5lnx)=x4+5x4lnx