y = 10 y = log x (the base of the log is 10, common logarithm) 10 = log x so that, 10^10 = x 10,000,000,000 = x
If x equals 10 and y equals 10, then 9x plus 8y equals 170.
An exponential function can be is of the form f(x) = a*(b^x). Some examples are f1(x) = 3*(10^x), or f2(x) = e^(-2*x). Note that the latter still fits the format, with b = e^(-2). The inverse is the logarithmic function. So for y = f1(x) = 3*(10^x), reverse the x & y, and solve for y:x = 3*(10^y)log(x) = log(3*(10^y)) = log(3) + log(10^y) = log(3) + y*log(10) = y*1 + log(3)y = log(x) - log(3) = log(x/3)The second function: y = e^(-2*x), the inverse is: x = e^(-2*y).ln(x) = ln(e^(-2*y)) = -2*y*ln(e) = -2*y*1y = -ln(x)/2 = ln(x^(-1/2))See related link for an example graph.
10
1
y = 10 y = log x (the base of the log is 10, common logarithm) 10 = log x so that, 10^10 = x 10,000,000,000 = x
y=logx becomes 10^y=x
The logarithm function is defined so that if y = 10x then log y = x So, if x = 1, y = 101 = 10 and so log 10 = 1
b y = xlog(b) + log(y) = log(x)
You have, y = 6 + log x anti log of it, 10y = (106) x
transitive property
Assuming that these are base 10 logs, which most of this notation are (though some insist on using the notation for base e logs):log m = xm = 10^xlog n = yn = 10^ymn = 10^x * 10^y= 10^(x+y)Depending on how you would prefer to write it.
If the log of x equals -3 then x = 10-3 or 0.001or 1/1000.
It cannot be done because the base for the second log is not given.
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If x equals 10 and y equals 10, then 9x plus 8y equals 170.
choose the negation of this statement. x plus y equals 10