2x - 1/x - 1 is defined only for x ≠ 1; (-∞, 1) u (1, ∞)
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Maximize z = 6x1 - 2x2+ 3x3 subject to 2x1 - x2 + 2x3 ≤ 2, x1+ 4x3 ≤ 4, x1, x2 , x3 ≥ 0.
Yes- a simple example is to think of two boxes with the same volume - 1cm3 the first a cube with sides 1cm and a surface area of 6 cm2 (6 equal sides) the second a box 2 X1 X1/2 the surface area is 2 sides of 2X1, 2 sides 1X1/2) and 2 sides 2X1/2 making in total 7 cm2
( x1 + x2) divided by 2 then (y1 +y 2) divided by 2
Rise divided by run. (Y2 - Y1) / (X2 - X1) - with (X1, Y1) and (X2, Y2) being two points on the graph.
5/8 x1/20 = 1/32