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Q: What is largest prime number that can divide 325 and 221 without any remainders?

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Written as a product of primes, 325 = 5^2 x 13 221 = 13 x 17 Therefore 13 goes into both 325 and 221

Repeatedly divide by 5 (noting the remainders) until the quotient is zero. Then write the remainders out in reverse order.

Any non-negative number smaller than 7.

Infinity: ∞

It is: 13

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The idea here is to factor each of the numbers. Then look for common factors, i.e., factors that appear in both numbers.

It is 34 because 34 is the largest number that will divide evenly into 1020 and 11594 leaving no remainders

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It is 75.

1 & 2 are the only non-zero remainders you can get from dividing a whole number by 3.

Written as a product of primes, 325 = 5^2 x 13 221 = 13 x 17 Therefore 13 goes into both 325 and 221

1 and 3 will divide into both numbers with no remainders

Repeatedly divide by 5 (noting the remainders) until the quotient is zero. Then write the remainders out in reverse order.

It is an odd number

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