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Q: What is largest prime number that can divide 325 and 221 without any remainders?

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Written as a product of primes, 325 = 5^2 x 13 221 = 13 x 17 Therefore 13 goes into both 325 and 221

13

It is: 13

I think you add the largest and small number, then divide the answer by 2

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17,303

It's the largest number that goes into both of them without remainders.

4

12 13 19

The idea here is to factor each of the numbers. Then look for common factors, i.e., factors that appear in both numbers.

It is 34 because 34 is the largest number that will divide evenly into 1020 and 11594 leaving no remainders

75

It is 75.

1 & 2 are the only non-zero remainders you can get from dividing a whole number by 3.

1 and 3 will divide into both numbers with no remainders

Written as a product of primes, 325 = 5^2 x 13 221 = 13 x 17 Therefore 13 goes into both 325 and 221

Repeatedly divide by 5 (noting the remainders) until the quotient is zero. Then write the remainders out in reverse order.

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