Written as a product of primes,
325 = 5^2 x 13
221 = 13 x 17
Therefore 13 goes into both 325 and 221
It is 13 because it is the HCF of 325 and 221
12 13 19
75
Repeatedly divide by 5 (noting the remainders) until the quotient is zero. Then write the remainders out in reverse order.
Any non-negative number smaller than 7.
17,303
It is 13 because it is the HCF of 325 and 221
The idea here is to factor each of the numbers. Then look for common factors, i.e., factors that appear in both numbers.
4
When you divide any integer by 11, the largest possible remainder you can get is 10. This is because when you divide a number by 11, the remainders can range from 0 to 10. In this case, if the number being divided is one less than a multiple of 11, the remainder will be the largest possible, which is 10.
12 13 19
You can divide a given number into an infinite number of other numbers to get different quotients or remainders.
75
It is 75.
1 & 2 are the only non-zero remainders you can get from dividing a whole number by 3.
Well, darling, when you divide any number by 5, the largest remainder you can get is 4. Why? Because when you divide by 5, the remainders can only be 0, 1, 2, 3, or 4. So, if you wanna keep it simple and sassy, the largest remainder with a divisor of 5 is 4.
Oh, dude, the largest prime number that goes evenly into 924 is 7. It's like the cool kid at the math party, just hanging out and dividing 924 without any remainders. So yeah, 7 is the lucky number that gets to evenly divide 924, like the VIP of prime numbers.