The locus of points equidistant from lines y = 0 and x = 3 is the line y = -x + 3.
All points less than 3 distant from point 'P' comprise a circle, centered at 'P', with a radius of 3, but NOT including the line that is the circumference of the circle.
The locus of points between 2 lines will always be another line that is halfway between the original 2 lines. In this case, that will be a line halfway between y=-2 and y=8, and since 3 is halfway between -2 and 8, the locus will be the line y=3.
The definition of locus given by Math Open Reference (mathopenref.com): A shape created by the set of points whose position satisfies a given set of rules.To be three inches from each of the two lines means that all the points of the locus are directly between the two given lines. Thus, the locus for this problem is a line parallel to and centered between the two parallel lines.i n c h e s0 3 6L1 locus L2| | || | || | || | || | || | |
Their x co-ordinate is -3.
The locus of points equidistant from lines y = 0 and x = 3 is the line y = -x + 3.
All points less than 3 distant from point 'P' comprise a circle, centered at 'P', with a radius of 3, but NOT including the line that is the circumference of the circle.
The locus of points between 2 lines will always be another line that is halfway between the original 2 lines. In this case, that will be a line halfway between y=-2 and y=8, and since 3 is halfway between -2 and 8, the locus will be the line y=3.
The definition of locus given by Math Open Reference (mathopenref.com): A shape created by the set of points whose position satisfies a given set of rules.To be three inches from each of the two lines means that all the points of the locus are directly between the two given lines. Thus, the locus for this problem is a line parallel to and centered between the two parallel lines.i n c h e s0 3 6L1 locus L2| | || | || | || | || | || | |
Their x co-ordinate is -3.
5-3/x2-0x
The run, combined with the rise (the distance in units up) creates the slope of a line. In the slope 5/3 , 5 is the rise and 3 is the run, meaning that to find the next point on the line you would first move up five units, then go to the right 3 units.
The origin, O is the point where the value on the number line is zero. Locate the a point 3 units to the left of the Origin, O and another point that is 5 units to the right of the origin. Join the two points with a straight line.
On a horizontal straight line, three units below the x axis. On a horizontal straight line, three units below the x axis. On a horizontal straight line, three units below the x axis. On a horizontal straight line, three units below the x axis.
None. If a point is 2 units from 'A' and equidistant from 'A' and 'B', then it also has to be2 units from 'B'.But the shortest distance between 'A' and 'B' is 6 units, and the point on that line that's equidistantfrom both of them is the point in the middle, which is 3 units from each.So a point equidistant from 'A' and 'B' must be 3 or more units from each one. 2 units won't do it.
2 points determine a line.
Points: (3, -4) and (3, 3) Distance: 7 units