log(314.25e) = log10(314.25) + log10e = 2.9316
logx(3) = log10(7) (assumed the common logarithm (base 10) for "log7") x^(logx(3)) = x^(log10(7)) 3 = x^(log10(7)) log10(3) = log10(x^(log10(7))) log10(3) = log10(7)log10(x) (log10(3)/log10(7)) = log10(x) 10^(log10(3)/log10(7)) = x
log10(225)2 equals 5.5327625985087111
Common
The natural logarithm is calculated to base e, where e is Euler's constant. For any number, x loge(x) = log10(x)/log10(e)
ln(x) = log10(X)/log10(e)
log(314.25e) = log10(314.25) + log10e = 2.9316
log10(0.083) = -1.0809 (rounded)
logx(3) = log10(7) (assumed the common logarithm (base 10) for "log7") x^(logx(3)) = x^(log10(7)) 3 = x^(log10(7)) log10(3) = log10(x^(log10(7))) log10(3) = log10(7)log10(x) (log10(3)/log10(7)) = log10(x) 10^(log10(3)/log10(7)) = x
One possible answer is log(330) Another is 1 + log(33)
Let us assume you have a Hydrochloric acid solution of 0.1 M. The pH is - log10[H+]. So log10[0.1] = -1 easy way to remember this is 103 =1000 log 101000 = 3 102 =100 log 10100 = 2 101 =10 log 1010 = 1 100 =1 log 101 = 0 10-1 =0.1 log 100.1 = -1 10-2 =0.01 log 100.01 = -2 So log10[0.1] = -1 and thus pH is - log10[H] = (minus minus 1) = 1
log5 +log2 =log(5x2)=log(10)=log10(10)=1
log10(225)2 equals 5.5327625985087111
log(6) or log10(6) = 0.778 (3sf). Therefore 100.778 = 6 (if you did not understand logarithms).
The little 'p' means -log10 (that's the negative log to base 10). Thus pH means -log10(Hydrogen ion concentration) → pH of the solution = -log10(7.0 x 10-2) ≈ 1.15
Common
The natural logarithm is calculated to base e, where e is Euler's constant. For any number, x loge(x) = log10(x)/log10(e)