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logx(3) = log10(7) (assumed the common logarithm (base 10) for "log7") x^(logx(3)) = x^(log10(7)) 3 = x^(log10(7)) log10(3) = log10(x^(log10(7))) log10(3) = log10(7)log10(x) (log10(3)/log10(7)) = log10(x) 10^(log10(3)/log10(7)) = x
The logarithm base 10 (log10) of 0.00000001 can be calculated as follows: 0.00000001 is equivalent to 10^-8. Therefore, log10(0.00000001) = log10(10^-8) = -8.
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The natural logarithm is calculated to base e, where e is Euler's constant. For any number, x loge(x) = log10(x)/log10(e)