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The expression for the product of ( m ) and 5 minus the quotient of ( t ) and 7 can be written mathematically as ( 5m - \frac{t}{7} ). This represents the result of multiplying ( m ) by 5 and then subtracting the result of dividing ( t ) by 7.
m=-0.2
-45m + 68 = 84m - 61 39m = 7 m = 7/39
The expression ( 7(m + 5)21 ) can be simplified by first distributing the 7 and the 21. This gives us ( 7 \times 21 \times (m + 5) = 147(m + 5) ). Thus, the expression simplifies to ( 147(m + 5) ).
2m^2 - 8 -First you should factor out a two. --> 2(m^2-4) -You now have something squared minus something else squared; You have m squared minus 2 squared. Whenever you have something squared minus something squared as you do in this case, there is a simple rule to remember: You can reduce that expression into the quantity of the square root of the first number or variable plus the square root of the second number or variable Times the quantity of the square root of the first number or variable minus the second number or variable squared. --> In the case of your expression: ----> 2(m+2)(m-2)<-----
The expression for the product of ( m ) and 5 minus the quotient of ( t ) and 7 can be written mathematically as ( 5m - \frac{t}{7} ). This represents the result of multiplying ( m ) by 5 and then subtracting the result of dividing ( t ) by 7.
12 - m
(81 - m2) = (9 - m)(9 + m)
m=-0.2
It is m + 7
-45m + 68 = 84m - 61 39m = 7 m = 7/39
To express "3 times the quantity m minus 7" mathematically, you would write it as 3(m - 7). This means you are multiplying the quantity m minus 7 by 3. To simplify this expression, you would distribute the 3 to both terms inside the parentheses, resulting in 3m - 21. So, "3 times the quantity m minus 7" simplifies to 3m - 21.
The expression ( 7(m + 5)21 ) can be simplified by first distributing the 7 and the 21. This gives us ( 7 \times 21 \times (m + 5) = 147(m + 5) ). Thus, the expression simplifies to ( 147(m + 5) ).
2m^2 - 8 -First you should factor out a two. --> 2(m^2-4) -You now have something squared minus something else squared; You have m squared minus 2 squared. Whenever you have something squared minus something squared as you do in this case, there is a simple rule to remember: You can reduce that expression into the quantity of the square root of the first number or variable plus the square root of the second number or variable Times the quantity of the square root of the first number or variable minus the second number or variable squared. --> In the case of your expression: ----> 2(m+2)(m-2)<-----
5m-t/7
10/5 = M - 9-7 => M = 3 and 2/7 = 23/7
m2 - 5m - 14 = 0(m - 7) (m + 2) = 0The equation is true ifm = 7orm = -2