You cannot "solve" a mean squared deviation". You can calculate it or use it, but there is nothing to solve!
Variance is the squared deviation from the mean. (X bar - X data)^2
First,find the mean of the set. Then,find the differences between every item and the mean Square them Find the mean of the squared differences The square root of that is the standard deviation
Standard deviation is equal to the square root of the variance. To arrive at this work out the mean, then subtract the mean and square the result of each number. Then work out the mean of those squared differences and take the square root of that.
None.The mean of a single number is itself.Therefore deviation from the mean = 0Therefore absolute deviation = 0Therefore mean absolute deviation = 0None.The mean of a single number is itself.Therefore deviation from the mean = 0Therefore absolute deviation = 0Therefore mean absolute deviation = 0None.The mean of a single number is itself.Therefore deviation from the mean = 0Therefore absolute deviation = 0Therefore mean absolute deviation = 0None.The mean of a single number is itself.Therefore deviation from the mean = 0Therefore absolute deviation = 0Therefore mean absolute deviation = 0
You cannot "solve" a mean squared deviation". You can calculate it or use it, but there is nothing to solve!
mean
No. The average of the deviations, or mean deviation, will always be zero. The standard deviation is the average squared deviation which is usually non-zero.
No, a standard deviation or variance does not have a negative sign. The reason for this is that the deviations from the mean are squared in the formula. Deviations are squared to get rid of signs. In Absolute mean deviation, sum of the deviations is taken ignoring the signs, but there is no justification for doing so. (deviations are not squared here)
A set of numbers will have a mean, which is defined as the sum of all the values divided by the number of values. Suppose this mean is m. For each of the values, the squared deviation is the square of the difference between that value and m. Algebraicly, if you have a set {x1, x2, x3, ... , xn}, whose mean is m, then the squared deviation from the mean for x1 is (x1 - m)2.
It is the standard deviation.
Variance
The standard deviation of a set of data is a measure of the spread of the observations. It is the square root of the mean squared deviations from the mean of the data.
No. Standard deviation is the square root of the mean of the squared deviations from the mean. Also, if the mean of the data is determined by the same process as the deviation from the mean, then you loose one degree of freedom, and the divisor in the calculation should be N-1, instead of just N.
Variance
If I have understood the question correctly, despite your challenging spelling, the standard deviation is the square root of the average of the squared deviations while the mean absolute deviation is the average of the deviation. One consequence of this difference is that a large deviation affects the standard deviation more than it affects the mean absolute deviation.
Variance is the squared deviation from the mean. (X bar - X data)^2