5n-2+2=4n 5n=4n n=0
12+4n = 2n12+4n-4n = 2n-4n12 = -2n-1/2(12 = -2n)-6 = n
The simplest, out of infinitely many possible answers, is the linear polynomial,U(n) = 4n - 1 for n = 1, 2, 3, ...
If you mean: 4n^2-60n+200 = 0 then the solutions are n = 10 or n = 5
The series is a(n) = 4n² +5n. . . and this is the general formula which also gives the nth term. When n = 1, 4n² + 5n = 4*1 + 5*1 = 9 When n = 2, 4n² + 5n = 4*4 + 5*2 = 26 . . .and so on When n = 5, 4n² + 5n = 4*25 + 5*5 = 125. The series can be determined using the Difference Technique. A second difference of 8 gives the first term 4n². . . . as a 2nd difference of 2 equates to n². After applying this to the original series, the revised series produces a 1st difference of 5, hence 5n.
4n-8=3n+2 4n=3n+2+8 4n=3n+10 4n-3n+10 n=10 N = 10
34 divide by 4n 34 - 4n cause 2nx2 is 2n+2n 2n is n+n so it is n+n+n+n =4n
5n-2+2=4n 5n=4n n=0
The first three terms of the nth term 4n-2 would be obtained by plugging in n=1, n=2, and n=3 into the expression. Therefore, the first term would be 4(1) - 2 = 2, the second term would be 4(2) - 2 = 6, and the third term would be 4(3) - 2 = 10. So, the first three terms are 2, 6, and 10 for the given nth term 4n-2.
n is a variable (representation of the number you are trying to find. 4n means 4 x n. EXAMPLE: If n = 2, then 4n = 4 x 2 = 8
12+4n = 2n12+4n-4n = 2n-4n12 = -2n-1/2(12 = -2n)-6 = n
You need the associative and commutative properties, but not the distributive property. n*4n*9 =n*(4n*9) (associative) = n*(9*4n) (commutative) = n*(36n) (associative) = 36n*n commutative = 36*n^2
-n + 4n = 4n - n = 3n Done!!!!!
The simplest, out of infinitely many possible answers, is the linear polynomial,U(n) = 4n - 1 for n = 1, 2, 3, ...
If you mean: 4n^2-60n+200 = 0 then the solutions are n = 10 or n = 5
The series is a(n) = 4n² +5n. . . and this is the general formula which also gives the nth term. When n = 1, 4n² + 5n = 4*1 + 5*1 = 9 When n = 2, 4n² + 5n = 4*4 + 5*2 = 26 . . .and so on When n = 5, 4n² + 5n = 4*25 + 5*5 = 125. The series can be determined using the Difference Technique. A second difference of 8 gives the first term 4n². . . . as a 2nd difference of 2 equates to n². After applying this to the original series, the revised series produces a 1st difference of 5, hence 5n.
2 - 4N = 2 + 3NSubtract 2 from each side:-4N = 3NAdd 4N to each side:0 = 7NN = 0That's the only value of ' N ' for which the given equationcan become a true statement.