Hückel's 4n+2 rulen is equal to 0 or any integer.
n=1 if aromatic should have 6 pi electrons
n=2 if aromatic should have 10 pi electrons
5n-2+2=4n 5n=4n n=0
12+4n = 2n12+4n-4n = 2n-4n12 = -2n-1/2(12 = -2n)-6 = n
The expression "n - 5 n - 2" can be simplified by combining like terms. First, rewrite it as (n - 5n - 2), which simplifies to (-4n - 2). Thus, the final simplified expression is (-4n - 2).
The simplest, out of infinitely many possible answers, is the linear polynomial,U(n) = 4n - 1 for n = 1, 2, 3, ...
Well, honey, it ain't rocket science. To multiply 4n by 2n, you simply multiply the coefficients (4 and 2) to get 8, and then multiply the variables (n and n) to get n^2. Put 'em together and you've got 8n^2. Easy peasy lemon squeezy!
4n-8=3n+2 4n=3n+2+8 4n=3n+10 4n-3n+10 n=10 N = 10
34 divide by 4n 34 - 4n cause 2nx2 is 2n+2n 2n is n+n so it is n+n+n+n =4n
5n-2+2=4n 5n=4n n=0
n is a variable (representation of the number you are trying to find. 4n means 4 x n. EXAMPLE: If n = 2, then 4n = 4 x 2 = 8
12+4n = 2n12+4n-4n = 2n-4n12 = -2n-1/2(12 = -2n)-6 = n
You need the associative and commutative properties, but not the distributive property. n*4n*9 =n*(4n*9) (associative) = n*(9*4n) (commutative) = n*(36n) (associative) = 36n*n commutative = 36*n^2
-n + 4n = 4n - n = 3n Done!!!!!
The simplest, out of infinitely many possible answers, is the linear polynomial,U(n) = 4n - 1 for n = 1, 2, 3, ...
Unless otherwise stated any series/sequence starts with n = 1 Then the first three terms are when n = 1, n= 2 and n = 3 and the series formula 4n - 2 gives the related results, 2, 6 and 10.
Well, honey, it ain't rocket science. To multiply 4n by 2n, you simply multiply the coefficients (4 and 2) to get 8, and then multiply the variables (n and n) to get n^2. Put 'em together and you've got 8n^2. Easy peasy lemon squeezy!
If you mean: 4n^2-60n+200 = 0 then the solutions are n = 10 or n = 5
The series is a(n) = 4n² +5n. . . and this is the general formula which also gives the nth term. When n = 1, 4n² + 5n = 4*1 + 5*1 = 9 When n = 2, 4n² + 5n = 4*4 + 5*2 = 26 . . .and so on When n = 5, 4n² + 5n = 4*25 + 5*5 = 125. The series can be determined using the Difference Technique. A second difference of 8 gives the first term 4n². . . . as a 2nd difference of 2 equates to n². After applying this to the original series, the revised series produces a 1st difference of 5, hence 5n.