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If n = 192 then n/4 = 6*8
8/16, 12/24, 16/32, 20/40
4n or n4
n (number) minus four ----->n-4
Let's denote the four consecutive integers as n, n+1, n+2, and n+3. The sum of these integers can be represented as n + (n+1) + (n+2) + (n+3) = 4n + 6. Given that the sum is -66, we can set up the equation 4n + 6 = -66. Solving for n, we find that n = -18. Therefore, the four consecutive integers are -18, -17, -16, and -15.