2n
16(2^n)(10)(2^n)=160[2^(2n)]=160(4^n)
1: (n-2)2 2: n-22 3: n+2n-2 4: n-2n+2 If I understand your question correctly (it is really confusing) then none of the expressions 2 3 or 4 equal the first expression.
To multiply the expressions (6n) and (2n), you multiply the coefficients (6 and 2) and the variable terms. This results in (6 \times 2 = 12) and (n \times n = n^2). Therefore, (6n \times 2n = 12n^2).
6n5
(2 / 3) times 3 = 2
16(2^n)(10)(2^n)=160[2^(2n)]=160(4^n)
6n2
The question is ambiguous. Does "2 over 3 times n" mean 2/(3*n) or (2/3)*n
"N cubed" refers to the mathematical operation of raising a number to the power of 3. This means multiplying the number by itself three times. For example, if n = 2, then n cubed would be 2 x 2 x 2, which equals 8. In general, n cubed can be represented as n^3 in mathematical notation.
The product of n multiplied by itself is written as n^2, which is read as "n squared." This is because when you multiply a number by itself, you are essentially squaring that number. So, n times n is equal to n^2.
The answer to this mathimatical equaion is N (+1+1x2) so u multiply N times postive 1 then add N times postive the N times 2 so it ends up N(1)+N(1)+N(2) then it is N1+N1+N2=N4
1: (n-2)2 2: n-22 3: n+2n-2 4: n-2n+2 If I understand your question correctly (it is really confusing) then none of the expressions 2 3 or 4 equal the first expression.
To multiply the expressions (6n) and (2n), you multiply the coefficients (6 and 2) and the variable terms. This results in (6 \times 2 = 12) and (n \times n = n^2). Therefore, (6n \times 2n = 12n^2).
n/2 times (n + 1)
6n5
(2 / 3) times 3 = 2
6(n + 2) = 6n + 12