2n
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16(2^n)(10)(2^n)=160[2^(2n)]=160(4^n)
1: (n-2)2 2: n-22 3: n+2n-2 4: n-2n+2 If I understand your question correctly (it is really confusing) then none of the expressions 2 3 or 4 equal the first expression.
To multiply the expressions (6n) and (2n), you multiply the coefficients (6 and 2) and the variable terms. This results in (6 \times 2 = 12) and (n \times n = n^2). Therefore, (6n \times 2n = 12n^2).
6n5
(2 / 3) times 3 = 2