16(2^n)(10)(2^n)=160[2^(2n)]=160(4^n)
1: (n-2)2 2: n-22 3: n+2n-2 4: n-2n+2 If I understand your question correctly (it is really confusing) then none of the expressions 2 3 or 4 equal the first expression.
6n5
(2 / 3) times 3 = 2
A number times itslef (n^2, or n x n). Sources I am an algebra 2 student.
16(2^n)(10)(2^n)=160[2^(2n)]=160(4^n)
6n2
The question is ambiguous. Does "2 over 3 times n" mean 2/(3*n) or (2/3)*n
"N cubed" refers to the mathematical operation of raising a number to the power of 3. This means multiplying the number by itself three times. For example, if n = 2, then n cubed would be 2 x 2 x 2, which equals 8. In general, n cubed can be represented as n^3 in mathematical notation.
The answer to this mathimatical equaion is N (+1+1x2) so u multiply N times postive 1 then add N times postive the N times 2 so it ends up N(1)+N(1)+N(2) then it is N1+N1+N2=N4
1: (n-2)2 2: n-22 3: n+2n-2 4: n-2n+2 If I understand your question correctly (it is really confusing) then none of the expressions 2 3 or 4 equal the first expression.
n/2 times (n + 1)
6n5
6(n + 2) = 6n + 12
Oh, dude, like, 3n times n is just 3n^2. It's like, you take 3 times n, and then multiply that by n again. So, it's basically n squared, but with a 3 in front. Easy peasy, lemon squeezy.
If we are to find the product of 5 and m and n/2 (which is half of n), we have: 5 times m times n/2 = 5 x m x n/2 = 5mn/2
(2 / 3) times 3 = 2