Q: What is perpendicular to x 2y 8?

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-2y=x+8 is the answer

y=(1/3)x+5

-6

-x+2y=8 Rewrite 2y-x=8 Add x to both sides 2y=x+8 Divide both sides by 2 y=0.5x+4 As can be seen by writing the equation in slope intercept,the y intercept is 4 Going back to the 2y=x+8,substituting 0 for y gives 0=x+8.The x intercept is -8.

2y = -6x + 8 is the given line Hence y = -3x + 4 the reduced given line. The gradianet of this line is '-3' ; the coefficient of 'x'. Using the eq'n ' mm'= -1 ' ,where 'm' & 'm'' are the given gradients. Hence substituting -3m' = -1 m' = -1/-3 = 1/3 The perpendicular gradient. Hence perpendicular line is y = (1/3)x + 5 or 3y = x + 15

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-2y=x+8 is the answer

8-x2y 8-2xy 2xy-8

y=(1/3)x+5

-6

-x+2y=8 Rewrite 2y-x=8 Add x to both sides 2y=x+8 Divide both sides by 2 y=0.5x+4 As can be seen by writing the equation in slope intercept,the y intercept is 4 Going back to the 2y=x+8,substituting 0 for y gives 0=x+8.The x intercept is -8.

perpendicular JEW

2y = -6x + 8 is the given line Hence y = -3x + 4 the reduced given line. The gradianet of this line is '-3' ; the coefficient of 'x'. Using the eq'n ' mm'= -1 ' ,where 'm' & 'm'' are the given gradients. Hence substituting -3m' = -1 m' = -1/-3 = 1/3 The perpendicular gradient. Hence perpendicular line is y = (1/3)x + 5 or 3y = x + 15

If you mean: x-2y = 8 then it is y = 0.5x-4.

Perpendicular to 2x - 3y = 8 through the point ( 2, 1 ) (Perpendicular means the slopes are negative inverses of each other) 3x+2y = 8

x+2y=8 Here you must add the expressions (2y - 2y = 0) 3x-2y=8 4x=16 Now you are left with a multiple of x so you can simply divide by 4 x=4 on both sides of the = 4+2y=8 Now you substitute x=4 into one of the original equations to find y 2y=4 y=2 Hope this helped.

Solve for y: 2x+2y=8 2y=-2x+8 y=-x+4 f(x)=-x+4 I think that's what you mean.

Two lines are perpendicular if the product of their slopes is -1. A straight line with an equation in the form: y = mx + c has slope m and y-intercept c. Given two lines y = mx +c and y = nx + d they are perpendicular if mn = -1. Examples: 1) are the two lines y = 2x and 2y = x + 2 perpendicular? y = 2x 2y = x + 2 → y = 1/2 x + 1 → product of slopes = 2 x 1/2 = 1 → the lines are not perpendicular 2) are the two lines y + 2x = 5 and 2y = x + 2 perpendicular? y + 2x = 5→ y = -2x + 5 2y = x + 2 → y = 1/2 x + 1 → product of slopes = -2 x 1/2 = -1 → the lines are perpendicular