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If you mean: x+2y = 8

Then: y = -1/2x+4

Perpendicular equation: y = 2x+4

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Q: What is perpendicular to x 2y 8?
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Related questions

-2y equals x plus 8?

-2y=x+8 is the answer


Simplify 8 -x 2y you 2y - x?

8-x2y 8-2xy 2xy-8


Click on the equation that represents the line perpendicular to 2y = -6x + 8 if the y-intercept is 5?

y=(1/3)x+5


What is x plus 2y equals -8 in slope intercept form?

-6


What is the x-int and y-int of -x plus 2y equals 8?

-x+2y=8 Rewrite 2y-x=8 Add x to both sides 2y=x+8 Divide both sides by 2 y=0.5x+4 As can be seen by writing the equation in slope intercept,the y intercept is 4 Going back to the 2y=x+8,substituting 0 for y gives 0=x+8.The x intercept is -8.


What type of lines are these x 2y 7 and 2x - y 7?

perpendicular JEW


What equation that represents the line perpendicular to 2y equals -6x plus 8 if the y-intercept is 5?

2y = -6x + 8 is the given line Hence y = -3x + 4 the reduced given line. The gradianet of this line is '-3' ; the coefficient of 'x'. Using the eq'n ' mm'= -1 ' ,where 'm' & 'm'' are the given gradients. Hence substituting -3m' = -1 m' = -1/-3 = 1/3 The perpendicular gradient. Hence perpendicular line is y = (1/3)x + 5 or 3y = x + 15


How do you Rewrite x - 2y 8 using function notation?

If you mean: x-2y = 8 then it is y = 0.5x-4.


Perpendicular to 2x plus 3y equals 8?

Perpendicular to 2x - 3y = 8 through the point ( 2, 1 ) (Perpendicular means the slopes are negative inverses of each other) 3x+2y = 8


Can anyone solve x plus 2y equals 8 and 3x-2y equals 8 as a simultaneous equation and show their working?

x+2y=8 Here you must add the expressions (2y - 2y = 0) 3x-2y=8 4x=16 Now you are left with a multiple of x so you can simply divide by 4 x=4 on both sides of the = 4+2y=8 Now you substitute x=4 into one of the original equations to find y 2y=4 y=2 Hope this helped.


How do you write 2x plus 2y equals 8 in function form?

Solve for y: 2x+2y=8 2y=-2x+8 y=-x+4 f(x)=-x+4 I think that's what you mean.


How can you determine if the given lines are perpendicular?

Two lines are perpendicular if the product of their slopes is -1. A straight line with an equation in the form: y = mx + c has slope m and y-intercept c. Given two lines y = mx +c and y = nx + d they are perpendicular if mn = -1. Examples: 1) are the two lines y = 2x and 2y = x + 2 perpendicular? y = 2x 2y = x + 2 → y = 1/2 x + 1 → product of slopes = 2 x 1/2 = 1 → the lines are not perpendicular 2) are the two lines y + 2x = 5 and 2y = x + 2 perpendicular? y + 2x = 5→ y = -2x + 5 2y = x + 2 → y = 1/2 x + 1 → product of slopes = -2 x 1/2 = -1 → the lines are perpendicular