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Let 'y' be the first equation and 'z' be the perpendicular one.

2y = -6x + 8

y = -3x + 4

A slope is perpendicular to another slope if and only if its slope is a negative reciporical of that slope. So

z = x/3 + b

and we know that b = 5, so

z = x/3 + 5

Q: What equation that represents the line perpendicular to 2y equals -6x plus 8 if the y-intercept is 5?

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y = - 1/3 x + any number.

It would be perpendicular to a line with the equation Y = 1/8 X.

"Y = any number" is perpendicular to "x = -3".

No because the slope of the second equation is 1/4 and for it to be perpendicular to the first equation it should be 1/3

In its general form of a straight line equation the perpendicular bisector equation works out as:- x-3y+76 = 0

Related questions

y = - 1/3 x + any number.

y=-x

y equals -1/3x plus 4/3

y = 1/3x+4/3

It would be perpendicular to a line with the equation Y = 1/8 X.

Convert the equation 2y = 5x - 4 into standard form then y = 2.5x - 2. Two straight lines are perpendicular if the product of their gradients is -1. Let the equation of the perpendicular line by y = mx + b. Then, 2.5m = -1 : m = -1/2.5 The y intercept occurs when x = 0. Then -3 = 0 + bc : b = -3 The equation of the perpendicular line is y = -1/2.5x -3 or 5y = -2x -15

"Y = any number" is perpendicular to "x = -3".

No because the slope of the second equation is 1/4 and for it to be perpendicular to the first equation it should be 1/3

It could be y = -x+5

In its general form of a straight line equation the perpendicular bisector equation works out as:- x-3y+76 = 0

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