-1
The x and y axes on the Cartesian plane are perpendicular to each other at the point of origin
3x + 2 = 3x + 6 This is not possible.
(2, -1)
Their graphs are.
-1
The x and y axes on the Cartesian plane are perpendicular to each other at the point of origin
It could be y = -2/3x+5
3x + 2 = 3x + 6 This is not possible.
(2, -1)
Their graphs are.
Perpendicular to 2x - 3y = 8 through the point ( 2, 1 ) (Perpendicular means the slopes are negative inverses of each other) 3x+2y = 8
If a line has equation y = mx + c, the perpendicular line has gradient -1/m A line perpendicular to 3x + y = 2 has equation 3y = x + c; the value for c will be determined by a point through which the line must pass.
3x + 2 = 0 3x = -2 x = -2/3
We need to get both equations into slope-intercept form. If they are parallel, they will have the same slope. If they are perpendicular, they will have slopes that when multiplied equal -1. (unless one line is horizontal and the other vertical) 3x+2y=5 2y=5-3x y=(-3/2)x+(5/2) 3x+2y=9 2y=9-3x y=(-3/2)x+(9/2) The two lines are parallel, since both slopes are equal to (-3/2).
4x plus 7 plus 3x equals 19 plus xx = 2
3x + 2 = -10 3x = -12 x = -4