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pi2 can be written as π(2) or π*2. All three notations indicate a product, or multiplication taking place between π and 2. The most accurate result is simply 2π, since π is a irrational constant, meaning its value never changes, and its decimal form goes on indefinitely.

If you want an actual approximation of 2π it's 6.28318530718

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Q: What is pi2?
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What is pi times pi exactly?

It is exactly pi2. Any other way you express it would be inexact. Pi, or any number that includes pi (like pi x 2, pi + 1, pi2, etc.) are irrational numbers - they can't be expressed as a fraction, with integers in the numerator and the denominator.It is exactly pi2. Any other way you express it would be inexact. Pi, or any number that includes pi (like pi x 2, pi + 1, pi2, etc.) are irrational numbers - they can't be expressed as a fraction, with integers in the numerator and the denominator.It is exactly pi2. Any other way you express it would be inexact. Pi, or any number that includes pi (like pi x 2, pi + 1, pi2, etc.) are irrational numbers - they can't be expressed as a fraction, with integers in the numerator and the denominator.It is exactly pi2. Any other way you express it would be inexact. Pi, or any number that includes pi (like pi x 2, pi + 1, pi2, etc.) are irrational numbers - they can't be expressed as a fraction, with integers in the numerator and the denominator.


What is the solution of Ln x equal x cube plus 3?

pi2


Convert -7pi2 radians to degrees?

-7 pi2 radians = -3,958.4 degrees (rounded)


What set of numbers does -0.002 belong?

Any set of numbers that contains it. For example: {1,2,3,-0.002} {sqrt(1), pi2, 1/93, -0.002, -73}


How do you solve for g in a simple pendulum problem?

For a simple pendulum, with very small, technically infinitesimal, swings, the period T is approximately 2 pisquare root (Length / gravity). From there, it is simple algebra.T2 = 4 pi2 length / gravitygravity = 4 pi2 length / T2For more information, including how to compensate for circular error introduced by non-infinitesimal swings, please see the Related Link below.