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Area of triangle = sqrt[p/2*(p/2-a)*(p/2-b)*(p/2-c)] where a, b and c are the sides.
To find the area of triangle OAP, where O is the origin (0,0) and A is the point (2, 6), we first need to determine the coordinates of point P where the tangent line intersects the x-axis. The slope of the radius OA at point A is -13/5, so the slope of line L, being tangent, is the negative reciprocal, 5/13. The equation of line L can be found using point A, and we can determine the x-intercept to find point P. Finally, the area of triangle OAP can be calculated using the formula: Area = 0.5 * base * height, with the base being the distance from O to P and the height being the y-coordinate of point A.
Often circles lines points et cetera are named.In this answer I call the circle C, the Tangent T, the point P, the center of the circle OThey are called just what your question asked:"The tangent to circle C through point P is T"P may not be inside C but may be on CIf P is outside C there are twotangents T1 and T2If P is on C there is one tangent TT is perpendicular to the radius at the point of tangency
Mateo's first step in constructing an equilateral triangle inscribed in a circle with center P is to draw the circle itself, ensuring that the radius is defined. Next, he can mark a point on the circumference of the circle to serve as one vertex of the triangle. From there, he will need to use a compass to find the other two vertices by measuring the same distance (the length of the triangle's side) along the circumference of the circle. Finally, he will connect the three points to form the equilateral triangle.
Objection! False! Nooo! :P ~
To find the image of ABC for a 180-degree counterclockwise rotation about point P, we would reflect each point of the triangle across the line passing through P. The resulting image of ABC would be a congruent triangle with its vertices in opposite positions relative to the original triangle.
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Three points on a triangle
Area of triangle = sqrt[p/2*(p/2-a)*(p/2-b)*(p/2-c)] where a, b and c are the sides.
The coordinates of the point P would be definitely 3 6.
To find the area of triangle OAP, where O is the origin (0,0) and A is the point (2, 6), we first need to determine the coordinates of point P where the tangent line intersects the x-axis. The slope of the radius OA at point A is -13/5, so the slope of line L, being tangent, is the negative reciprocal, 5/13. The equation of line L can be found using point A, and we can determine the x-intercept to find point P. Finally, the area of triangle OAP can be calculated using the formula: Area = 0.5 * base * height, with the base being the distance from O to P and the height being the y-coordinate of point A.
If a remains the right triangle, No
Often circles lines points et cetera are named.In this answer I call the circle C, the Tangent T, the point P, the center of the circle OThey are called just what your question asked:"The tangent to circle C through point P is T"P may not be inside C but may be on CIf P is outside C there are twotangents T1 and T2If P is on C there is one tangent TT is perpendicular to the radius at the point of tangency
The perimeter of a triangle is found by adding all 3 sides of the triangle. This is most commonly expressed using the formula for a triangle's perimeter: a+b+c=P. Where P is perimeter and a,b,and c are the three sides.
Draw a picture of this you will see that you can form a triangle with the radius of the circle being 1. This is the hypotenus of the triangle Using trig, x = cos 50 y = sin 50 P is (x,y) = P is (cos 50,sin 50) = (0.643, 0.766)
F the triangle thingy and t the triangle thingy then p