10 ft X 10 ft square tank will hold 1000 cubic feet of water or 7480.51 gallons 10 ft round tank will hold 785 cubic feet of water or 5872.207 gallons
Given that this stands out a mile as almost certainly a school homework question, to answer directly would be to make me complicit in cheating. So I will tell you how to calculate it, which would appear to be the point of the question: 1) The relationship between depth and pressure of water is linear. 2) If water X ft deep exerts a pressure of P lb/in2, then water of Y ft deep will obviously exert a pressure of P(Y/X) lbs/in2 Given thats information you can now solve the original question.
This is a really fiendish problem, but we may have outsmarted it.Ordinarily, the dimensions of the pool wouldn't matter, because the pressure onlydepends on the depth of the water ... you always find the same pressure at thesame depth below the surface, whether you're in a pond, a lake, a bathtub, anocean, or a swimming pool. So our first instinct was to calculate the pressure at6-ft down, since your pool is 6-ft deep.But wait! Why is the quantity of water given ? Could it be that the pool is notcompletely full and sloshing over the rim ?Volume of the full pool = (12 x 30 x 6) = 2,160 cubic feet = 16,157.9 gallons.Ah hah! The pool is not full!Those 11,500 gallons fill it to only (11,500/16,157.9) x (6-ft) = 4.2704 feet. (rounded)The pressure under 4.2704-ft of water is 1.841 psi(rounded)(Using 5 psi = 11.6 ft of water, which we found somewhere on the www.)
An aquarium is 10 ft long, 3 ft wide, and is filled with water to a depth of 7 ft. Water weighs 62.4 pounds per cubic foot. What is the volume and weight of the water in the tank
10 * 10 = 100 square feet!
No, the fluid pressure increases with depth underwater. The pressure at 10 ft underwater will be greater than the pressure at 5 ft underwater due to the weight of the water above exerting a greater force at greater depths.
The water pressure at a depth of 900 ft is approximately 390 psi.
One foot is a unit of distance. One atmosphere is a unit of pressure (force per unit area). 10 atmospheres is equivalent to about 21,162 lb/ft^2 (pounds per square foot). At 339 feet under water, the pressure is approximately 10 atmospheres (assuming water density is 1000 kg/m^3).
133.64psi
Because the water is forcing bubbles from you and it is sucking all the air out of your ears which causes the pressure to hurt.
10 feet x 0.433 psi/ft = 4.33 psi at the base of the cylinder.
Fluid pressure increases with depth in a fluid due to the weight of the fluid above it. This is known as hydrostatic pressure.
The pressure of water at a depth of 10000 ft is approximately 4330 psi (pounds per square inch). This is calculated using the formula P = ρgh, where P is the pressure, ρ is the density of water, g is acceleration due to gravity, and h is the depth of the water.
'Hydrostatic Pressure' is the Term used for 'the force exerted by a body of fluid at rest. The pressure increases with increase in depth.There are two ways to Calculate water (clean water) pressure at any depth (both yields almost same results):1. The Hydrostatic pressure of water is 0.433 Psi/ft (Pounds per square inch Per feet). So at 5000 feet, the pressure is: 0.433 Psi/ft. * 5000 ft = 2165 Psianother way to go about it is:2. Water pressure increases at 14.7 psi every 34 feet depth. Thus Pressure at 5000 ft will be: (5000 ft / 34 ft) * 14.7 psi = 2162 Psi.
10 ft X 10 ft square tank will hold 1000 cubic feet of water or 7480.51 gallons 10 ft round tank will hold 785 cubic feet of water or 5872.207 gallons
The pressure is only dependent on the height of water above the measuring point. 1 psi corresponds to a height of 2.3 ft, so 8 ft = 3.5 psi The pressure is only dependent on the height of water above the measuring point. 1 psi corresponds to a height of 2.3 ft, so 8 ft = 3.5 psi
Using the ideal gas law equation P1V1 = P2V2, with initial pressure (P1) = 10 psig, initial volume (V1) = 30 ft^3, final volume (V2) = 25 ft^3, we can solve for the final pressure (P2). (10 psig * 30 ft^3) / 25 ft^3 = 12 psig, so the new pressure would be 12 psig.