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1620
The 8051 microcontroller employs several addressing modes, including: Immediate Addressing Mode: The operand is specified in the instruction itself. Example: MOV A, #25H moves the hexadecimal value 25 into the accumulator. Register Addressing Mode: The operand is in a register. Example: MOV A, R0 moves the content of register R0 into the accumulator. Direct Addressing Mode: The operand's address is given directly in the instruction. Example: MOV A, 30H moves the content of memory location 30H into the accumulator. Indirect Addressing Mode: The address of the operand is held in a register. Example: MOV A, @R1 moves the content of the memory location pointed to by register R1 into the accumulator.
Assuming we're not dealing with complex numbers, the domain is:R = {x Є R | x >= 0}, or equivalently, R0+, or [0,∞]All three of the above terms say the same thing, the domain is all the real numbers greater than or equal to zero.
In assembly language and computer architecture, registers are often denoted by the symbol % or a specific prefix depending on the architecture. For example, in x86 assembly, registers are typically represented with a % symbol (e.g., %eax, %ebx), while in ARM assembly, they are usually referred to by their names without any prefix (e.g., r0, r1). In some assembly languages, registers may also be indicated by a specific letter or abbreviation.
R= R0 * [1 + rho( t2-t1 ) ] so from this equation , rho= R-R0/[R0(t2-t1)] where rho- coefficient of resisivity R-resistance at any time t R0- resistance at 00C t2-final temperature t1-initial temperature
Example for System/360 CPU: L R0,A A R0,B ST R0,SUM ... A DS F B DS F SUM DS F
565 r0
Clr psw.3 clr psw.4 mov r1, 05h mov r0, #50h dcr r1 mov 10h, @r0 up: inc r0 mov a, @r0 cjne a, 10h dn ajmp dn: jnc next mov 10h,a next: djnz r1 up *:ajmp *
No. It depends on how the range is defined.y = x2 is not onto R but can be made onto by changing the range to R0+.No. It depends on how the range is defined.y = x2 is not onto R but can be made onto by changing the range to R0+.No. It depends on how the range is defined.y = x2 is not onto R but can be made onto by changing the range to R0+.No. It depends on how the range is defined.y = x2 is not onto R but can be made onto by changing the range to R0+.
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Mov tmod, #01h mov r0, #20 back:mov tl0,96 mov th0,60 setb tr0 again:jnb tf0, again clr tr0 clr tf0 djnz r0, back
An opcode is a single instruction in assembly language. An operand is the data it does something with.For example, in "MOV r0, #0C", MOV is the opcode ("move this value into this register"), while r0 (register 0) and #0C (the number 12) are operands.
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9 times with no remainder
You are probably thinking in the definition of Moment of Inertia of a system ofpoints with mass mi at distance ri from the rotation axis;I = Σ m(ri)2If mT is the total mass of the disc with radius r0, the product mT(r0)2 would bethe Moment of Inertia of a point with mass mT at a distance r0 from the axis ofrotation. But for a disc, the mass is distributed through his radius from r = 0 tor = r0, and so you would expect a smaller value of I.If we start from I's above given definition, which is a summation of finite terms,and put it as a summation of differential terms (an integration), then theexpression can apply to a body, and we have,I = ⌠m d(r2) = ⌠m 2rdr = 2⌠m rdr (1)now we need to introduce m as a function of r, m = f(r).Let h be the thickness of the disc, and D the density of the disc material.Then,m = density x volume = D (πr2h} (2)ec. (2) in (1)I = 2⌠D(πr2h) rdr (3)taking constants out of the integralI = 2πhD⌠r3dr (4)integrating ec. (4) from r = 0 to r = r0I = 2πhD (1/4)(r0)4 (5)density D is D = mT/VT (6) where VT is the disc total volumeVT = π(r0)2h (7)ec. (7) in (6),D = mT/[π(r0)2h] (8)finally, ec. (8) in (5)gives I = (1/2) mT (r0)2Q.E.D