Assuming we're not dealing with complex numbers, the domain is:
R = {x Є R | x >= 0}, or equivalently, R0+, or [0,∞]
All three of the above terms say the same thing, the domain is all the real numbers greater than or equal to zero.
Domain is greater than or equal to zero. same with range
Yes, because when x equals 1, the square root of x is rational and the square root of -x is irrational, and when x equals -1, the square root of x is irrational and the square root of -x is rational.
y=(√1)-x2 The domain is the set of numbers that "x" can be. In this equation "x" can be any real number. The domain for this problem would be (-inf,inf) *Inf= Infinity*
The square root of a value v is a number x such that, x multiplied by x equals v. Note that -x is also a square root.
Plus or minus the base. If the base is X and you square it, you get X2. If you take the square root of that, you get Plus or Minus X. This is because X*X equals X2 and -X*-X also equals X2.
what is the domain of g(x) equals square root of x plus 1? √(x+1) ≥ 0 x+1≥0 x≥-1 Domain: [-1,∞)
Domain is greater than or equal to zero. same with range
x
Yes, because when x equals 1, the square root of x is rational and the square root of -x is irrational, and when x equals -1, the square root of x is irrational and the square root of -x is rational.
Domian is x>-6 Range is y> or equal to 0
If x equals the square root of ...., then you already have solved for x
14
y=(√1)-x2 The domain is the set of numbers that "x" can be. In this equation "x" can be any real number. The domain for this problem would be (-inf,inf) *Inf= Infinity*
The square root of a value v is a number x such that, x multiplied by x equals v. Note that -x is also a square root.
Plus or minus the base. If the base is X and you square it, you get X2. If you take the square root of that, you get Plus or Minus X. This is because X*X equals X2 and -X*-X also equals X2.
x=square root (-2) =i(square root of 2)WHERE i2 =-1
x = 9