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How do you write a formula for the number of seconds x in a hours b minutes and c seconds?

x= 3600a + 60b + c ( a hr x 3600 sec / hr ) + ( b min x 60 sec / min ) + c sec = x sec


What is the integral sec x?

ln|sec x + tan x| + C.


When was J. R. C Hr Sec School created?

J. R. C Hr Sec School was created in 1991.


What is the anti derivative of sec?

The antiderivative of sec(x) is given by the formula: [ \int \sec(x) , dx = \ln | \sec(x) + \tan(x) | + C ] where ( C ) is the constant of integration. This result can be derived using a clever manipulation involving multiplying by a specific form of 1.


What is integral of SECx?

The integral of sec(x) with respect to x is ln|sec(x) + tan(x)| + C, where C is the constant of integration. This result can be derived using integration techniques such as substitution or integration by parts. The integral of sec(x) is a common integral in calculus and is often used in trigonometric integrals.


What shall be the fruit juice pasteurization temperature and time?

Typical fruit juice pasteurization temperature is from 85 degree C to 95 degree C and 45 sec to 15 sec. Example if 90 degree C temperature then 20 sec is fine although it varies with pH, sugar content, viscosity, etc.


How do you find wavelength?

C=AV OR A=C/V WHICH IS THE SPEED OF LIGHT 3.00 × 108 m/sec


What is a Three letter word for dry as wine ends in c?

Sec


What is c kunalan's record timing for 100m in 1968?

10.38 sec


How do you write a c program to convert time in sec to time?

main() { int sec=00,min=00,hr=00; printf("Enter time in seconds"); scanf("%d",&sec); if (sec<60) printf("%d :%d : %d",hr,min,sec); else if(sec>=60) min=int(sec/60); sec=int(sec%60); printf("%d: %d : %d",hr,min,sec); else if (sec>=3600) min=int(sec/60); sec=int(sec/60) hr=int(min/60); printf("%d : %d : %d",hr,sec,min); }


What is the formular for the speed of light?

In the USA . . . c = 186,282.397 miles/secIn the rest of the world . . . c = 299,792,458 meters/sec


How do you integrate x secx?

To integrate ( x \sec x ), you can use integration by parts. Let ( u = x ) and ( dv = \sec x , dx ). Then, ( du = dx ) and ( v = \ln |\sec x + \tan x| ). Applying the integration by parts formula, you get: [ \int x \sec x , dx = x \ln |\sec x + \tan x| - \int \ln |\sec x + \tan x| , dx + C ] where ( C ) is the constant of integration. The second integral may require further techniques to evaluate.