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How do you write a formula for the number of seconds x in a hours b minutes and c seconds?
x= 3600a + 60b + c ( a hr x 3600 sec / hr ) + ( b min x 60 sec / min ) + c sec = x sec
How do you find wavelength?
C=AV OR A=C/V WHICH IS THE SPEED OF LIGHT 3.00 × 108 m/sec
What is the differentiate of y equals tanx plus c?
y' = (sec(x))^2
What is the wavelength that has a frequency of 5.11 x 1011 hz?
c = fλ ; where c is speed of light, f is frequency in Hertz (sec-1), and λ is wavelength in meters. Take c = 3 x 108 m/s. (3 x 108 m/sec)/(5.11 x 1011 sec-1) = 5.871 x 10-4 m, or 587.1 μm (micrometers).
Solve sec2x equals secx plus 2?
You must mean, either,(1) sec2 x = sec x + 2, or(2) sec(2x) = sec x + 2.Let's first assume that you mean:sec2 x = sec x + 2;whence,if we let s = sec x, we have,s2 = s + 2,s2 - s - 2 = (s - 2)(s + 1) = 0, ands = 2 or -1; that is,sec x = 2 or -1.As, by definition,cos x = 1/sec x ,this means thatcos x = ½ or -1.Therefore, providing that the first assumption is correct,x = 60°, 180°, or 300°; or,if you prefer,x = ⅓ π, π, or 1⅔ π.Now, let's assume, instead, that you mean:sec(2x) = sec x + 2;whence,1/(cos(2x) = (1/cos x) + 2.If we let c = cos x,then we have the standard identity,2c2 - 1 = cos (2x); and,thus, it follows that1/(cos(2x) = 1/(2c2 - 1)= (1/c) + 2 = (1 + 2c)/c.This gives,1/(2c2 - 1) = (1 + 2c)/c;(2c2 - 1)(2c + 1) = 4c3 + 2c2 - 2c - 1 = c; and4c3 + 2c2 - 3c - 1 = (c + 1)(4c2 - 2c - 1) = 0.As our concern is only with real roots,c = cos x = -1; and,therefore, providing that the second assumption is correct,x = 180°; or,if you like,x = π.
