Write sec x as a function of sines and cosines (in this case, sec x = 1 / cos x). Then use the division formula to take the first derivative. Take the derivative of the first derivative to get the second derivative. Reminder: the derivative of sin x is cos x; the derivative of cos x is - sin x.
An integral and an anti-derivative are the same thing. Integration means the process of finding the integral, just as anti-differentiation means the process of finding the anti-derivative.
find anti derivative of f(x) 5x^4/3 + 8x^5/4
anti derivative of ax^n is (a/n+1)x^(n+1) a is a const n is power of variable and answere6x^2
According to Wolfram Alpha, input:integral csc x it is -log[cot(x) + csc(x)] + constant You can verify this by taking the derivative of the purported integral.
The derivative of sec(x) is sec(x) tan(x).
You can take out any constant from a derivative. In other words, this is the same as 5 times the derivative of sec x.
Write sec x as a function of sines and cosines (in this case, sec x = 1 / cos x). Then use the division formula to take the first derivative. Take the derivative of the first derivative to get the second derivative. Reminder: the derivative of sin x is cos x; the derivative of cos x is - sin x.
The anti derivative of negative sine is cosine.
sec(x)tan(x)
derivative of sec2(x)=2tan(x)sec2(x)
.0015x2
the derivative of tangent dy/dx [ tan(u) ]= [sec^(2)u]u' this means that the derivative of tangent of u is secant squared u times the derivative of u.
An integral and an anti-derivative are the same thing. Integration means the process of finding the integral, just as anti-differentiation means the process of finding the anti-derivative.
x squared
The idea is to use the chain rule. Look up the derivative of sec x, and just replace "x" with "5x". Then multiply that with the derivative of 5x.
find anti derivative of f(x) 5x^4/3 + 8x^5/4