Write sec x as a function of sines and cosines (in this case, sec x = 1 / cos x). Then use the division formula to take the first derivative. Take the derivative of the first derivative to get the second derivative. Reminder: the derivative of sin x is cos x; the derivative of cos x is - sin x.
An integral and an anti-derivative are the same thing. Integration means the process of finding the integral, just as anti-differentiation means the process of finding the anti-derivative.
find anti derivative of f(x) 5x^4/3 + 8x^5/4
anti derivative of ax^n is (a/n+1)x^(n+1) a is a const n is power of variable and answere6x^2
According to Wolfram Alpha, input:integral csc x it is -log[cot(x) + csc(x)] + constant You can verify this by taking the derivative of the purported integral.
The derivative of sec(x) is sec(x) tan(x).
You can take out any constant from a derivative. In other words, this is the same as 5 times the derivative of sec x.
Write sec x as a function of sines and cosines (in this case, sec x = 1 / cos x). Then use the division formula to take the first derivative. Take the derivative of the first derivative to get the second derivative. Reminder: the derivative of sin x is cos x; the derivative of cos x is - sin x.
The anti derivative of negative sine is cosine.
sec(x)tan(x)
derivative of sec2(x)=2tan(x)sec2(x)
.0015x2
the derivative of tangent dy/dx [ tan(u) ]= [sec^(2)u]u' this means that the derivative of tangent of u is secant squared u times the derivative of u.
An integral and an anti-derivative are the same thing. Integration means the process of finding the integral, just as anti-differentiation means the process of finding the anti-derivative.
The idea is to use the chain rule. Look up the derivative of sec x, and just replace "x" with "5x". Then multiply that with the derivative of 5x.
x squared
find anti derivative of f(x) 5x^4/3 + 8x^5/4