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What are 3 consecutive numbers when the first and thirds sum is 40?
19,20,21
What is the sum of the first 80 consecutive odd numbers?
40 * * * * * The correct answer is 6400.
Find the sum of first 20 even numbers. sum?
The sum of the first 20 even numbers... is 110
What is the sum of the first 20 even numbers?
2+4+6+8+10........+40=420
What is the sum of the fist 40 even numbers?
You can use the formula for the sum of an arithmetic series to calculate that quickly. (Of course, you can also type the numbers into Excel, and get the sum - but that doesn't scale well - e.g., it won't work well if you are then asked, for instance, to get the sum of the first million even numbers.)
What is the sum of the first 40 odd numbers?
The sum of the first 40 odd numbers is 1,600.
What is the sum of the first 40 evn numbers?
The sum of the first 40 even numbers is 1,640.
What are 3 consecutive numbers when the first and thirds sum is 40?
19,20,21
What is the sum of the first 80 consecutive odd numbers?
40 * * * * * The correct answer is 6400.
Find the sum of first 20 even numbers. sum?
The sum of the first 20 even numbers... is 110
How can I solve the 40 odd numbers?
1 ,3, 5, 7 ,9......, 77, 79. Sum of first 40 odd numbers is 1600. This is the answer
What is the answer when you add all numbers from 40 to 60?
The sum of the numbers 1 to 39 = 39 x 40 ÷ 2 = 780 The sum of the numbers 1 to 60 = 60 x 61 ÷ 2 = 1830 Therefore the sum of the numbers 40 to 60 = 1830 - 780 = 1050
What is the sum of the first 20 even numbers?
2+4+6+8+10........+40=420
What is the average of 7 2 9 22?
Sum of numbers = 40 Count of numbers = 4 Average = Sum/Count = 40/4 = 10
What is the sum of the first 50 numbers?
The sum of the first 50 whole numbers is 1,225.
Sum of first 1000 numbers?
The sum of the first 1,000 whole numbers is 499,500.
The sum of 5 numbers is 200 what is the average of the numbers?
The average of five numbers whose sum is 200 will always be 40, no matter which numbers you choose. When finding an average, you add up the numbers (find the sum of the set), then divide by the number of terms. In this case, the sum will always be 200, and there will always be five terms. This will always result in an average of 40. Ex/ 1 + 2 + 3 + 4 + 190 = 200 200 / 5 = 40 40 + 40 + 80 + 24 + 16 = 200 200 / 5 = 40
