The sum of the first 40 odd numbers is 1,600.
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How many odd numbers are there from 16 to 30? Seven {7} odd numbers
There are 40 odd numbers between 20 and 100. Remember that an odd number is every second number. There are 80 numbers between 20 and 100, so there are 40 odd numbers and 40 even numbers.
1 + 3 + 5 + 7 + 9 + 11 + 13 + 15 + 17 + 19 + 21 + 23 + 25 + 27 + 29 + 31 + 33 + 35 + 37 + 39 = 400 1,3,5,7,9,11,13,15,17,19,21,23,25,27,29,31,33,35,37,39 above are the first 20 odds If you add the first to the last you get 40 If you add the second to the second from last you get 40 It doesn't matter which numbers you add first so long as you add them all up there are 10 pairs of numbers totaling 40 so the sum is 400
I don't believe this is possible. The formula for an odd number is (2n+1) where n is any integer. So, for seven odd numbers added together... {a,b,c,d,e,f,g are the integers) (2a +1) + (2b +1) + ... + (2g+1) = 2(a+b+c+d+e+f+g) + 7 = 2(h) + 7 h is an integer 2h + 7 must be an odd number, thus it can't equal 40
The sum of the numbers 1 to 39 = 39 x 40 ÷ 2 = 780 The sum of the numbers 1 to 60 = 60 x 61 ÷ 2 = 1830 Therefore the sum of the numbers 40 to 60 = 1830 - 780 = 1050