How many odd numbers are there from 16 to 30? Seven {7} odd numbers
I don't believe this is possible. The formula for an odd number is (2n+1) where n is any integer. So, for seven odd numbers added together... {a,b,c,d,e,f,g are the integers) (2a +1) + (2b +1) + ... + (2g+1) = 2(a+b+c+d+e+f+g) + 7 = 2(h) + 7 h is an integer 2h + 7 must be an odd number, thus it can't equal 40
There are 40 odd numbers between 20 and 100. Remember that an odd number is every second number. There are 80 numbers between 20 and 100, so there are 40 odd numbers and 40 even numbers.
1 + 3 + 5 + 7 + 9 + 11 + 13 + 15 + 17 + 19 + 21 + 23 + 25 + 27 + 29 + 31 + 33 + 35 + 37 + 39 = 400 1,3,5,7,9,11,13,15,17,19,21,23,25,27,29,31,33,35,37,39 above are the first 20 odds If you add the first to the last you get 40 If you add the second to the second from last you get 40 It doesn't matter which numbers you add first so long as you add them all up there are 10 pairs of numbers totaling 40 so the sum is 400
The sum of the numbers 1 to 39 = 39 x 40 ÷ 2 = 780 The sum of the numbers 1 to 60 = 60 x 61 ÷ 2 = 1830 Therefore the sum of the numbers 40 to 60 = 1830 - 780 = 1050
40 * * * * * The correct answer is 6400.
1 ,3, 5, 7 ,9......, 77, 79. Sum of first 40 odd numbers is 1600. This is the answer
The answer is 1600. All you have to do is times the number given into itself. Example first 50 odd numbers would be 50x 50= 2500.
The sum of the first 40 whole numbers is 780.
The sum of the first 40 even numbers is 1,640.
How many odd numbers are there from 16 to 30? Seven {7} odd numbers
There are 20 odd numbers in 40.
There can be no number with an odd sum of 8 because 8 is not odd!
There is a 40% chance that it will be an odd number. Explanation: The first five prime numbers are 2, 3, 5, 7, and 11. If one of the two numbers chosen is 2, the sum of the two numbers will be odd. 2 + 3 = 5 2 + 5 = 7 2 + 7 = 9 2 + 11= 13 But, if both numbers chosen are odd, the sum will be an even number. 3 + 5 = 8 3 + 7 = 10 3 + 11 = 14 5 + 7 = 12 5 + 11 = 16 7 + 11 = 18 So, there are four possible combinations out of 10 that result in a sum that is odd. Another way to do this, without listing the possible combinations, is to determine the chance of randomly selecting the 2. Two numbers are being chosen from five, so there is a 2/5 = 40% chance of selecting a 2, which means the sum will be odd.
I don't believe this is possible. The formula for an odd number is (2n+1) where n is any integer. So, for seven odd numbers added together... {a,b,c,d,e,f,g are the integers) (2a +1) + (2b +1) + ... + (2g+1) = 2(a+b+c+d+e+f+g) + 7 = 2(h) + 7 h is an integer 2h + 7 must be an odd number, thus it can't equal 40
The odd numbers between 40 and 53 are 41,43,45,47,49,51.
19,20,21