If the sequence is taken to start 1,1,2,... then the 100th term is 354,224,848,179,261,915,075 And you've got to hope I have typed that in correctly!
"The recursive form is very useful when there aren't too many terms in the sequence. For instance, it would be fairly easy to find the 5th term of a sequence recursively, but the closed form might be better for the 100th term. On the other hand, finding the closed form can be very difficult, depending on the sequence. With computers or graphing calculators, the 100th term can be found quickly recursively."
Well, honey, it looks like we've got ourselves an arithmetic sequence here. Each term is increasing by 6, 8, 10, and 12 respectively. So, if we keep following that pattern, the 100th term would be 6 more than the 99th term, which is 12 more than the 98th term, and so on. Just keep adding 14 to each successive term and you'll eventually get to that 100th term.
you replace the "n" with ahundred e.g... if it's 2n+1, you will go 2x100+ 1 which is 201
It is the sequence of first differences. If these are all the same (but not 0), then the original sequence is a linear arithmetic sequence. That is, a sequence whose nth term is of the form t(n) = an + b
If the sequence is taken to start 1,1,2,... then the 100th term is 354,224,848,179,261,915,075 And you've got to hope I have typed that in correctly!
a + 99d where 'a' is the first term of the sequence and 'd' is the common difference.
Oh, dude, chill out with the math! So, to find the 100th term in that sequence, you just need to figure out the pattern. Looks like each term is increasing by 6, right? So, just do a little math dance and you'll get the 100th term. It's gonna be... 596! Or you could just keep adding 6 to the last term 99 times, but who's got time for that?
"The recursive form is very useful when there aren't too many terms in the sequence. For instance, it would be fairly easy to find the 5th term of a sequence recursively, but the closed form might be better for the 100th term. On the other hand, finding the closed form can be very difficult, depending on the sequence. With computers or graphing calculators, the 100th term can be found quickly recursively."
The sequence given is an arithmetic sequence where each term is the sum of the previous term and a constant difference. The constant difference in this sequence is increasing by 1 each time, starting with 2. To find the 100th term, we can use the formula for the nth term of an arithmetic sequence: ( a_n = a_1 + (n-1)d ), where ( a_n ) is the nth term, ( a_1 ) is the first term, ( n ) is the term number, and ( d ) is the common difference. Plugging in the values, we get ( a_{100} = 1 + (100-1)2 = 1 + 99*2 = 1 + 198 = 199 ). Therefore, the 100th term in the sequence is 199.
ive been told u hve 2 times sumfin bii sumfin
Well, honey, it looks like we've got ourselves an arithmetic sequence here. Each term is increasing by 6, 8, 10, and 12 respectively. So, if we keep following that pattern, the 100th term would be 6 more than the 99th term, which is 12 more than the 98th term, and so on. Just keep adding 14 to each successive term and you'll eventually get to that 100th term.
It is 354,224,848,179,261,915,075.
you replace the "n" with ahundred e.g... if it's 2n+1, you will go 2x100+ 1 which is 201
Centennial
Lets say the formula is 5n+6 you would times the 5 by 100 - 500, and then add on the 6! So your answer would be 506.
502