no
3x + y = -4 -3x -3x y = - 4 -3x now plug in points!+++To clarify the principle, re-arrange the equation so it reads as "y = [something done to x]" then calculate a table of points for the plot itself.
Yes and they add up to 11x
There are an infinite number of lines that are all parallel to [ y = 3x + 6 ].Here are ten of them to get you started:y = 3x - 1y = 3xy = 3x + 1y = 3x + 2y = 3x + 3y = 3x + 4y = 3x + 5y = 3x + 5.99y = 3x + 6.001y = 3x + 7.etc.
x + y = 12Since y=3x, we can stick '3x' in wherever we see 'y':x + 3x = 12Tidy up the left side:4x = 12Divide each side by 4:x = 3y = 9
no
In the 3x table 5 is prime (3 x 5 = 15), 7 is prime (3 x 7 = 21), and 11 is prime (3 x 11 = 33).
y=3x+7 7x +3y=63
3x + y = -4 -3x -3x y = - 4 -3x now plug in points!+++To clarify the principle, re-arrange the equation so it reads as "y = [something done to x]" then calculate a table of points for the plot itself.
50
3x + 3x + 3x = 3* (3x) = 9x
Since you add up the 'x''s (i.e. (2x) (3x) (4x) = 24x cubed) 6x2
3x^5 If these are 5 of 3x multiplied together the it must be (3x)^5 =3^5 times x^5
3x**2+x-10 Multiply first and last terms 3*-10=-30 Find factors of -30 that add up to second term 6+-5=1 rewrite 3x**2-5x+6x-10 Factor pairs of terms 3x**2-5x+6x-10 = x(3x-5)+2(3x-5) Factor x(3x-5)+2(x-5) = (x+2)(3x-5)
3x. 15x - 9x = 6x 9x - 6x = 3x 6x - 3x = 3x 3x - 3x = 0
Suppose the middle one is 3x, then the other two are 3x-3 and 3x+3. Their product is (3x-3)*3x*(3x+3) = 3x*(3x-3)*(3x+3) = 27x(x-1)*(x+1) = 27x*(x2-1) So 27x*(x2-1) = 648 x*(x2-1) = 648/27 = 24 ie x3 - x - 24 = 0 or x3 - 3x2 + 3x2 - 9x + 8x - 24 = 0 ie (x - 3)(x2 + 3x + 8) = 0 The only integer solution is x = 3 So the three numbers are 3*(3-1), 3*3 and 3*(3+1) = 6, 9 and 12.
9x2 + 6x + 1 = 9x2 + 3x + 3x + 1 = 3x(3x + 1) + 1(3x + 1) = (3x + 1)(3x + 1) or (3x +1)2