3x**2+x-10
Multiply first and last terms
3*-10=-30
Find factors of -30 that add up to second term
6+-5=1
rewrite
3x**2-5x+6x-10
Factor pairs of terms
3x**2-5x+6x-10 = x(3x-5)+2(3x-5)
Factor
x(3x-5)+2(x-5) = (x+2)(3x-5)
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n(2n - 1)(2n + 7)
6(b - ac + b2 - bc)
(4x - 3)(2x + 3)
(x-1)(x+2)
(x - 1)(5x + 7)
x sq equalls 36 and x equalls plus or minus 6
(x squared plus the square root of 2) times (x squared minus the square root of 2).
There is no rational factorisation.
There are no rational factors.
n(2n - 1)(2n + 7)
(a - 2)(a^2 + 6)
(b-c)(a+b)-ac
(3y - 5)(y + 5)
(x + 3)(3x - 2)
(7a - 1)(6a + 1)
it is (x-y)(x-y) :)
(3r - 2)(3r - 2) or (3r - 2) squared.