3x**2+x-10
Multiply first and last terms
3*-10=-30
Find factors of -30 that add up to second term
6+-5=1
rewrite
3x**2-5x+6x-10
Factor pairs of terms
3x**2-5x+6x-10 = x(3x-5)+2(3x-5)
Factor
x(3x-5)+2(x-5) = (x+2)(3x-5)
n(2n - 1)(2n + 7)
6(b - ac + b2 - bc)
(x - 1)(5x + 7)
(x-1)(x+2)
(4x - 3)(2x + 3)
2x^(2) + 72 Factors to 2( x^(2) + 36) s(x^(2) + 6^(2)) Does NOT factor. NB Remember . two squared terms with a positive(+) between them does NOT factor!!!! However, two squared terms with a negative(-) between DOES factor . e.g. x^(2) + 6^(2) Does NOT factor x^(2) - 6^(2) factors to ( x - 6)( x + 6 ) Note the different signs. Similarly 8^(2) + 6^(2) does NOT factor 8^(2) - 6^(2) factors to (8 - 6)(8 + 6) Or using the ~Pythagorean Equation. h^(2) = a^(2) + b^(2) Does NOT factors However, a^(2) = h^(2) - b^(2) factors to a^(2) = (h - b)(h + b) .
(x squared plus the square root of 2) times (x squared minus the square root of 2).
There are no rational factors.
There is no rational factorisation.
n(2n - 1)(2n + 7)
(3y - 5)(y + 5)
(a - 2)(a^2 + 6)
(b-c)(a+b)-ac
(x + 3)(3x - 2)
(7a - 1)(6a + 1)
(3r - 2)(3r - 2) or (3r - 2) squared.
it is (x-y)(x-y) :)