3x**2+x-10
Multiply first and last terms
3*-10=-30
Find factors of -30 that add up to second term
6+-5=1
rewrite
3x**2-5x+6x-10
Factor pairs of terms
3x**2-5x+6x-10 = x(3x-5)+2(3x-5)
Factor
x(3x-5)+2(x-5) = (x+2)(3x-5)
n(2n - 1)(2n + 7)
6(b - ac + b2 - bc)
(x - 1)(5x + 7)
(x-1)(x+2)
(4x - 3)(2x + 3)
(x squared plus the square root of 2) times (x squared minus the square root of 2).
There are no rational factors.
There is no rational factorisation.
n(2n - 1)(2n + 7)
(b-c)(a+b)-ac
(a - 2)(a^2 + 6)
3x^(2) +9x - 2x -6 Collect 'like terms'. Hence 3x^(2) + 7x - 6 Next write down all the factors of '3' and '6' Hence 3 ; 1' & 3' 6 ; 1,6 ; 2,3. From these pairs of number we select a pair from each coefficient, that add/multiply to '7' . Hence (3' x 3 ) & (1' x 2) ; NB 'dashes' (') to indicate source of numbers. Write up brackets (3x 2)(x 3) -2)(x + 3) Next we notice that the '6' is negative, so the two signs are different (+/-) The '7x' is positive , so the larger number takes the positive sign . Hence (3x - 2)(x + 3)
(3y - 5)(y + 5)
(7a - 1)(6a + 1)
(3r - 2)(3r - 2) or (3r - 2) squared.
it is (x-y)(x-y) :)
6(b - ac + b2 - bc)