Any number that you choose can be the eighth term. It is easy to find a rule based on a polynomial of order 5 such that the first five numbers are as listed in the question followed by the chosen number in eighth position. There are also non-polynomial solutions. Short of reading the mind of the person who posed the question, there is no way of determining which of the infinitely many solutions is the "correct" one.
The simplest answer, based on the following polynomial of order 4 U(n) = (376*n^4 - 3384*n^3 + 11186*n^2 - 15369*n + 7227)/3 for n = 1, 2, 3, ...gives U(8) = 135889.
To find the 8th term in the sequence 15, 24, 42, 78, 150, we first identify a pattern in the differences between consecutive terms. The differences are 9, 18, 36, and 72, which suggest that the differences themselves are doubling (approximately). Continuing this pattern, the next differences would be 144 and 288. Thus, the 6th term would be 150 + 144 = 294, the 7th term would be 294 + 288 = 582, and the 8th term would be 582 + 576 = 1158. Therefore, the 8th term is 1158.
If you have this series: 1,2,3,4,5,6,7,8The 8th term is 8 and the n-th term is n.But if you have this series: 2,4,6,8,10,12,14,16The 8th term is 16 and the n-th term is 2n
To find the 8th term of a geometric sequence, we need the first term and the common ratio. However, you've only provided a single term (13927) without context. If 13927 is the first term, the 8th term would be calculated as ( a_8 = a_1 \cdot r^{(n-1)} ) where ( r ) is the common ratio and ( n ) is the term number. Without knowing the common ratio, the 8th term cannot be determined. Please provide the common ratio for a complete answer.
the answer for the above question is -2187
654
It is 917969.
There are an infinite number of possible answers - there are an infinite number of formulae that can be found to give t{1..5} = {12, 59, 294, 1469, 7344} which will give different values for t8. eg: t{n} = (376n⁴ - 3384n³ + 11186n² - 15369n + 7227)/3 gives t{1..5} = {12, 59, 294, 1469, 7344}, and t8 = 135889. t{n} = (-4929n⁵ + 76943n⁴ - 446037n³ +1198513n² -1473498n + 649296)/24 also gives t{1..5} = {12, 59, 294, 1469, 7344}, but t8 = -381656. However, the solution your teacher is probably expecting is based on the fact that: U1 = 12 U{n} = 5U{n-1} - 1 for n ≥ 2 This leads to: t1 = 12 t{n} = 12 + 47 × 5ⁿ⁻² for n ≥ 2 → t8 = 917969
To find the 8th term in the sequence 15, 24, 42, 78, 150, we first identify a pattern in the differences between consecutive terms. The differences are 9, 18, 36, and 72, which suggest that the differences themselves are doubling (approximately). Continuing this pattern, the next differences would be 144 and 288. Thus, the 6th term would be 150 + 144 = 294, the 7th term would be 294 + 288 = 582, and the 8th term would be 582 + 576 = 1158. Therefore, the 8th term is 1158.
294
If you have this series: 1,2,3,4,5,6,7,8The 8th term is 8 and the n-th term is n.But if you have this series: 2,4,6,8,10,12,14,16The 8th term is 16 and the n-th term is 2n
90
Well, darling, the sequence you've got there is just the perfect squares of numbers. The 8th term would be the square of the 8th number, which is 64. So, the 8th term of the sequence 1, 4, 9, 16, 25 is 64. Keep those brain cells sharp, honey!
It is: 1 1 2 3 5 8 13 and 21 which is the 8th term
90
1/8th
48
To find the 8th term of the sequence with the rule 3n + 4, you would substitute n = 8 into the formula. This gives you 3(8) + 4 = 24 + 4 = 28. Therefore, the 8th term of the sequence is 28.