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The given sequence is the sequence of perfect squares starting from 1. The nth term of this sequence can be represented as n^2. Therefore, the 8th term would be 8^2, which equals 64. So, the 8th term of the sequence 1, 4, 9, 16, 25 is 64.

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βˆ™ 1mo ago
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βˆ™ 9y ago
The 8th term is 64.

The sequence is the squares of the counting numbers. The nth term is given by t(n) = n².
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Q: What is the 8th term of the sequence 1 4 9 16 25?
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