use pethagoreon theorm.
Example: a=? b=3 c=5
since your trying to find a, your equation would be
a² + 3 ²= 5²
a² + 9 = 25
deriving the formula to get "a"
25 - 9 = 16
a² = 16
√ a = √ 16
a = 4
The altitude of a right triangle if the base is 96 and the hypotenuse is 240 is: 229.87
No. Not if the triangle is right angled (the intersection is AT the right vertex) or obtuse angled (intersection outside).
Sqrt x2+y2
If one leg of a right angled triangle is regarded as the altitude then the other leg is the base.
The altitude formula is like this: Area x 2 divided by the base ( Ax2:b) The area formula is base x height divided by 2
It is: c2-b2 = a2 whereas c is the hypotenuse, b is the base and a is the altitude
The altitude of a right triangle if the base is 96 and the hypotenuse is 240 is: 229.87
Any right triangle resting on a leg.
1)1/2*base*altitude
The Formula is Base*Height, or 1/2 Height (altitude of the triangle) * Base (of the Triangle) * height (Height of the prism)
actually it's a2+b2=c2 the altitude is a or b and can be found by c2/a2*=b2* * a2 and b2 are interchangeable. by the way this only works with right triangles.
No. Not if the triangle is right angled (the intersection is AT the right vertex) or obtuse angled (intersection outside).
To find the altitude of a triangle, we can use the formula: area = 0.5 * base * altitude. Given that the area is 45 cm² and the base is 15 cm, we can plug these values into the formula: 45 = 0.5 * 15 * altitude. Solving for altitude, we get altitude = 45 / (0.5 * 15) = 45 / 7.5 = 6 cm. Therefore, the altitude of the triangle is 6 cm.
I would hazard a guess and say it was 10.
Sqrt x2+y2
The altitude of an equilateral triangle is (√3)/2*a. where 'a' is the side of the triangle. It can be just find by giving a perpendicular to the base of the triangle, the base of the triangle become a/2 and one side is a. so by applying Pythagoras theorem we will get the desired formula.
If one leg of a right angled triangle is regarded as the altitude then the other leg is the base.