The altitude of a right triangle if the base is 96 and the hypotenuse is 240 is: 229.87
No. Not if the triangle is right angled (the intersection is AT the right vertex) or obtuse angled (intersection outside).
Sqrt x2+y2
If one leg of a right angled triangle is regarded as the altitude then the other leg is the base.
The altitude formula is like this: Area x 2 divided by the base ( Ax2:b) The area formula is base x height divided by 2
It is: c2-b2 = a2 whereas c is the hypotenuse, b is the base and a is the altitude
The altitude of a right triangle if the base is 96 and the hypotenuse is 240 is: 229.87
Any right triangle resting on a leg.
1)1/2*base*altitude
The Formula is Base*Height, or 1/2 Height (altitude of the triangle) * Base (of the Triangle) * height (Height of the prism)
actually it's a2+b2=c2 the altitude is a or b and can be found by c2/a2*=b2* * a2 and b2 are interchangeable. by the way this only works with right triangles.
Well, isn't that a happy little question! The altitude of a triangle is always perpendicular to the base it intersects. It's like a little friend that helps the triangle stand tall and proud. Just remember, in the world of triangles, altitudes are always there to lend a hand and make everything more balanced and beautiful.
No. Not if the triangle is right angled (the intersection is AT the right vertex) or obtuse angled (intersection outside).
I would hazard a guess and say it was 10.
Sqrt x2+y2
The altitude of an equilateral triangle is (√3)/2*a. where 'a' is the side of the triangle. It can be just find by giving a perpendicular to the base of the triangle, the base of the triangle become a/2 and one side is a. so by applying Pythagoras theorem we will get the desired formula.
If one leg of a right angled triangle is regarded as the altitude then the other leg is the base.