The altitude of a right triangle if the base is 96 and the hypotenuse is 240 is: 229.87
No. Not if the triangle is right angled (the intersection is AT the right vertex) or obtuse angled (intersection outside).
Sqrt x2+y2
If one leg of a right angled triangle is regarded as the altitude then the other leg is the base.
The altitude formula is like this: Area x 2 divided by the base ( Ax2:b) The area formula is base x height divided by 2
It is: c2-b2 = a2 whereas c is the hypotenuse, b is the base and a is the altitude
The altitude of a right triangle if the base is 96 and the hypotenuse is 240 is: 229.87
Any right triangle resting on a leg.
1)1/2*base*altitude
The Formula is Base*Height, or 1/2 Height (altitude of the triangle) * Base (of the Triangle) * height (Height of the prism)
actually it's a2+b2=c2 the altitude is a or b and can be found by c2/a2*=b2* * a2 and b2 are interchangeable. by the way this only works with right triangles.
An altitude intersects another altitude at the centroid. FALSE - The altitudes intersect at what is called the orthocenter.An altitude intersects another altitude at its midpoint. FALSE - The altitudes will meet at random intersection points.An altitude is present inside a triangle FALSE - The altitude can be outside the triangle.An altitude makes a right angle with a side of the triangle. TRUE - An altitude is the line from a vertex to the opposite side, forming a right angle.
No. Not if the triangle is right angled (the intersection is AT the right vertex) or obtuse angled (intersection outside).
I would hazard a guess and say it was 10.
Sqrt x2+y2
The altitude of an equilateral triangle is (√3)/2*a. where 'a' is the side of the triangle. It can be just find by giving a perpendicular to the base of the triangle, the base of the triangle become a/2 and one side is a. so by applying Pythagoras theorem we will get the desired formula.
If one leg of a right angled triangle is regarded as the altitude then the other leg is the base.