0
Add your answer:
Earn +20 pts
Area of a square that has side 15cm?
225 cm squared
Can 15cm 6cm and 9cm form a triangle?
No. The sum of the lengths of any two sides of a triangle must be greater that the third. Here 6 + 9 = 15, not > 15.
A triangle sides are 8Cm 11Cm and 15Cm What is the triangles area?
A triangle with side a: 8, side b: 11, and side c: 15 cm has an area of 42.85 square cm.
What is the surface of 15cm x 15cm?
15*15 = 225 square centimetres.
An isosceles triangle has two equal sides that are 15cm long and two equal angles of 62 degrees calculate the length of the third side?
first find the unknown angle, 180o - (62o+62o) = 56o next use the law of sines to find the other side: sin 62o / 15cm = sin 56o / X Solving for x, X = 14.08 cm
The area of a triangle is 45cm2 the base of the triangle is 6cm what is the height of the triangle?
Area of a triangle = 1/2 x base x altitude(height)On putting given values, we get45cm2 = 1/2 x 6cm x height(altitude)cm45 = 3 x altitudealtitude = 15 cmAnswer to the question is 15cm.
What is a triangle with sides 11cm 15cm 11cm?
Isosceles
Area of a square that has side 15cm?
225 cm squared
What is the area of a triangle with a base of 10cm and a height of 15cm?
To find the area of a triangle, you use the formula: Area = 1/2 * base * height. Plugging in the values, we get Area = 1/2 * 10cm * 15cm = 75 square cm. Therefore, the area of the triangle with a base of 10cm and a height of 15cm is 75 square cm.
How many triangles have the perimeter of 15cm?
To determine the number of triangles with a perimeter of 15cm, we need to consider the possible side lengths that can form a triangle. The triangle inequality theorem states that the sum of the lengths of any two sides of a triangle must be greater than the length of the third side. With a perimeter of 15cm, the possible side lengths could be (5cm, 5cm, 5cm) for an equilateral triangle, (6cm, 5cm, 4cm) for an isosceles triangle, or (7cm, 5cm, 3cm) for a scalene triangle. Therefore, there are 3 possible triangles that can have a perimeter of 15cm.
Can you construct a triangle that has side lengths 11cm 12cm and 15cm?
Yes
Is 7cm 11cm 15cm a right triangle?
To determine if the given measurements form a right triangle, we can use the Pythagorean theorem. In a right triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the other two sides. So, in this case, we would check if (7^2 + 11^2 = 15^2) holds true. Calculating this, we get (49 + 121 = 225), which simplifies to (170 \neq 225). Therefore, the given measurements do not form a right triangle.
What is the area of a right triangle with sides of 8cm 15cm 17cm?
60 cm2
What is the length of the hypotenuse of a right triangle where the two sides are 15cm and 15cm long?
Using Pythagoras' theorem: 15 times the square root of 2 cm in length
What is the missing length of the right triangle which measures 15 cm by 13 cm?
We don't know whether the 15cm happens to be the hypotenuse (longest side) of the right triangle. It makes a big difference. -- If the 15cm is the longest side, then the third side is 7.483 cm. (rounded) -- If the 13cm and the 15cm are the "legs", then the hypotenuse is 19.849 cm. (rounded)
The perimeter of an equilateral triangle is 45 centimetersFind the length of an altitude?
Each side of the triangle is 45cm/3=15cm. The altitude divides the base into two equal segments of 7.5cm. This results in a right triangle with hypotenuse 15 cm and base 7.5cm. Pythagorus tells us a2+b2=c2 where a=altitude, b=base, c=hypotenuse. a2=c2-b2=152-7.52=225-56.25=168.75, a=12.99cm. Alternatively, the 3 angles of an equilateral triangle are all 60 degrees. The altitude divides one of these angles into two 30 degree angles. The cosine of 30 degrees is the opposite divided by the adjacent side. The adjacent side is the altitude. Thus a/c=cosine of 30 degrees, a=c X cos30 degrees = 15X0.866=12.99cm
What is the value of h in a right angled triangle with 31° and 15cm?
Following the symbols in the image: Assuming 15cm corresponds to a (the line adjacent to the angle), then you need to use the cosine formula cos(ø) = a/h cos(31º) = 15cm/h h*cos(31º) = (15cm/h) * h h*cos(31º) = 15cm * 1 h*cos(31º)/cos(31º) = 15cm/cos(31º) h*1 = 15cm/cos(31º) h = 16.398
