225 cm squared
No. The sum of the lengths of any two sides of a triangle must be greater that the third. Here 6 + 9 = 15, not > 15.
A triangle with side a: 8, side b: 11, and side c: 15 cm has an area of 42.85 square cm.
15*15 = 225 square centimetres.
first find the unknown angle, 180o - (62o+62o) = 56o next use the law of sines to find the other side: sin 62o / 15cm = sin 56o / X Solving for x, X = 14.08 cm
No. 7 squared plus 11 squared does not equal 15 squared.
Area of a triangle = 1/2 x base x altitude(height)On putting given values, we get45cm2 = 1/2 x 6cm x height(altitude)cm45 = 3 x altitudealtitude = 15 cmAnswer to the question is 15cm.
Isosceles
225 cm squared
75
Yes
60 cm2
Using Pythagoras' theorem: 15 times the square root of 2 cm in length
We don't know whether the 15cm happens to be the hypotenuse (longest side) of the right triangle. It makes a big difference. -- If the 15cm is the longest side, then the third side is 7.483 cm. (rounded) -- If the 13cm and the 15cm are the "legs", then the hypotenuse is 19.849 cm. (rounded)
Each side of the triangle is 45cm/3=15cm. The altitude divides the base into two equal segments of 7.5cm. This results in a right triangle with hypotenuse 15 cm and base 7.5cm. Pythagorus tells us a2+b2=c2 where a=altitude, b=base, c=hypotenuse. a2=c2-b2=152-7.52=225-56.25=168.75, a=12.99cm. Alternatively, the 3 angles of an equilateral triangle are all 60 degrees. The altitude divides one of these angles into two 30 degree angles. The cosine of 30 degrees is the opposite divided by the adjacent side. The adjacent side is the altitude. Thus a/c=cosine of 30 degrees, a=c X cos30 degrees = 15X0.866=12.99cm
Following the symbols in the image: Assuming 15cm corresponds to a (the line adjacent to the angle), then you need to use the cosine formula cos(ø) = a/h cos(31º) = 15cm/h h*cos(31º) = (15cm/h) * h h*cos(31º) = 15cm * 1 h*cos(31º)/cos(31º) = 15cm/cos(31º) h*1 = 15cm/cos(31º) h = 16.398
A triangle with those measurements would just form a straight line.