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Q: Find the altitude of a triangle whose area is 45cm squared and 15cm?

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225 cm squared

No. The sum of the lengths of any two sides of a triangle must be greater that the third. Here 6 + 9 = 15, not > 15.

A triangle with side a: 8, side b: 11, and side c: 15 cm has an area of 42.85 square cm.

15*15 = 225 square centimetres.

15cm 12cm

Related questions

No. 7 squared plus 11 squared does not equal 15 squared.

Area of a triangle = 1/2 x base x altitude(height)On putting given values, we get45cm2 = 1/2 x 6cm x height(altitude)cm45 = 3 x altitudealtitude = 15 cmAnswer to the question is 15cm.

Isosceles

225 cm squared

75

Yes

60 cm2

Using Pythagoras' theorem: 15 times the square root of 2 cm in length

We don't know whether the 15cm happens to be the hypotenuse (longest side) of the right triangle. It makes a big difference. -- If the 15cm is the longest side, then the third side is 7.483 cm. (rounded) -- If the 13cm and the 15cm are the "legs", then the hypotenuse is 19.849 cm. (rounded)

Following the symbols in the image: Assuming 15cm corresponds to a (the line adjacent to the angle), then you need to use the cosine formula cos(ø) = a/h cos(31º) = 15cm/h h*cos(31º) = (15cm/h) * h h*cos(31º) = 15cm * 1 h*cos(31º)/cos(31º) = 15cm/cos(31º) h*1 = 15cm/cos(31º) h = 16.398

Each side of the triangle is 45cm/3=15cm. The altitude divides the base into two equal segments of 7.5cm. This results in a right triangle with hypotenuse 15 cm and base 7.5cm. Pythagorus tells us a2+b2=c2 where a=altitude, b=base, c=hypotenuse. a2=c2-b2=152-7.52=225-56.25=168.75, a=12.99cm. Alternatively, the 3 angles of an equilateral triangle are all 60 degrees. The altitude divides one of these angles into two 30 degree angles. The cosine of 30 degrees is the opposite divided by the adjacent side. The adjacent side is the altitude. Thus a/c=cosine of 30 degrees, a=c X cos30 degrees = 15X0.866=12.99cm

A triangle with those measurements would just form a straight line.

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