5
18 = 2 * 3 * 370 = 2 * 5 * 7Thus:LCM = 2*3*3*5*7 = 630HCF = 2
You find the HCF of the two numbers, not their product. Example: 30 and 42 Factor them. 2 x 3 x 5 = 30 2 x 3 x 7 = 42 Select the common factors. 2 x 3 = 6, the HCF
hcf(16×27×49, 8×2725) = 8×27 = 216 Using prime factorisation: 16×27×49 = 2⁴ × 3³ × 7² 8×27×125 = 2³ × 3³ × 5³ → hcf = 2³ × 3³ = 8×27 = 216
1. HCF by factorisation Method: HCF is the product of common factors of all the numbers. Example: HCF of 24, 48, 60 First find the prime factors of these numbers 2 |24 2|48 2|60 24= 2*2*2*3 2|12 2|24 2|30 48= 2*2*2*2*3 2|6 2|12 3|15 60= 2*2*3*5 3|3 2|6 5|5 HCF= 2*2*3=12 |1 3|3 |1 |1 2. Division Method: Divide the larger number by the smaller number. Now divide the devisor by the remainder. Continue the process till the remainder is zero. Now this last devisor is the HCF of those two numbers. Repeat the process between this HCF and the other number. 48)60(1 48 12)48(4 48 0 12)60(5 60 0 Ans: 12
16 48 = 2^4 x 3 224 = 2^5 x 7 hcf = 2^4 = 16
The GCF is 42.
The GCF is 1.
hcf(14, 30) = 2 lcm(14, 30) = 210 14 = 2 x 7 30 = 2 x 3 x 5 hcf = 2 lcm = 2 x 3 x 5 x 7 = 210
18 = 2 * 3 * 370 = 2 * 5 * 7Thus:LCM = 2*3*3*5*7 = 630HCF = 2
hcf = 15 lcm = 3510 270 = 2 x 33 x 5 195 = 3 x 5 x 13 hcf = 3 x 5 = 15 lcm = 2 x 33 x 5 x 13 = 3510
The Highest Common Factor (HCF) of 480 and 1080 is the largest positive integer that divides both numbers without leaving a remainder. To find the HCF, we need to factorize both numbers into their prime factors. The prime factors of 480 are 2^5 x 3 x 5, and the prime factors of 1080 are 2^3 x 3^3 x 5. To find the HCF, we take the common prime factors with the lowest exponent, which are 2^3 x 3 = 24. Therefore, the HCF of 480 and 1080 is 24.
You find the HCF of the two numbers, not their product. Example: 30 and 42 Factor them. 2 x 3 x 5 = 30 2 x 3 x 7 = 42 Select the common factors. 2 x 3 = 6, the HCF
The Highest Common Factor (HCF) of 120 and 180 is the largest number that divides both 120 and 180 without leaving a remainder. To find the HCF, we need to factorize both numbers into their prime factors. The prime factorization of 120 is 2^3 * 3 * 5, and the prime factorization of 180 is 2^2 * 3^2 * 5. To find the HCF, we take the product of the common prime factors with the lowest exponent, which is 2^2 * 3 = 12. Therefore, the HCF of 120 and 180 is 12.
The HCF of the given numbers is 1
hcf(16×27×49, 8×2725) = 8×27 = 216 Using prime factorisation: 16×27×49 = 2⁴ × 3³ × 7² 8×27×125 = 2³ × 3³ × 5³ → hcf = 2³ × 3³ = 8×27 = 216
1. HCF by factorisation Method: HCF is the product of common factors of all the numbers. Example: HCF of 24, 48, 60 First find the prime factors of these numbers 2 |24 2|48 2|60 24= 2*2*2*3 2|12 2|24 2|30 48= 2*2*2*2*3 2|6 2|12 3|15 60= 2*2*3*5 3|3 2|6 5|5 HCF= 2*2*3=12 |1 3|3 |1 |1 2. Division Method: Divide the larger number by the smaller number. Now divide the devisor by the remainder. Continue the process till the remainder is zero. Now this last devisor is the HCF of those two numbers. Repeat the process between this HCF and the other number. 48)60(1 48 12)48(4 48 0 12)60(5 60 0 Ans: 12
10 = 2 x 5 18 = 2 x 3 x 3 HCF = 2 x 3 x 5 x 3 = 90