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What is the HCF of 210 and 84?

The GCF is 42.


What is the HCF of 5 and 3?

The GCF is 1.


What is the hcf and LCM of 14 and 30?

hcf(14, 30) = 2 lcm(14, 30) = 210 14 = 2 x 7 30 = 2 x 3 x 5 hcf = 2 lcm = 2 x 3 x 5 x 7 = 210


What is the LCM and the HCF of 18 and 70?

18 = 2 * 3 * 370 = 2 * 5 * 7Thus:LCM = 2*3*3*5*7 = 630HCF = 2


What is the HCF and LCM of 270 and 195?

hcf = 15 lcm = 3510 270 = 2 x 33 x 5 195 = 3 x 5 x 13 hcf = 3 x 5 = 15 lcm = 2 x 33 x 5 x 13 = 3510


What is the HCF of 480 and 1080?

The Highest Common Factor (HCF) of 480 and 1080 is the largest positive integer that divides both numbers without leaving a remainder. To find the HCF, we need to factorize both numbers into their prime factors. The prime factors of 480 are 2^5 x 3 x 5, and the prime factors of 1080 are 2^3 x 3^3 x 5. To find the HCF, we take the common prime factors with the lowest exponent, which are 2^3 x 3 = 24. Therefore, the HCF of 480 and 1080 is 24.


How do you find HCF of product of 2 nos?

You find the HCF of the two numbers, not their product. Example: 30 and 42 Factor them. 2 x 3 x 5 = 30 2 x 3 x 7 = 42 Select the common factors. 2 x 3 = 6, the HCF


What is the HCF of 120 and 180?

The Highest Common Factor (HCF) of 120 and 180 is the largest number that divides both 120 and 180 without leaving a remainder. To find the HCF, we need to factorize both numbers into their prime factors. The prime factorization of 120 is 2^3 * 3 * 5, and the prime factorization of 180 is 2^2 * 3^2 * 5. To find the HCF, we take the product of the common prime factors with the lowest exponent, which is 2^2 * 3 = 12. Therefore, the HCF of 120 and 180 is 12.


What is the hcf of 21 5 and 3?

The HCF of the given numbers is 1


What is the HCF of 16x27x49 and 8x27x125?

hcf(16×27×49, 8×2725) = 8×27 = 216 Using prime factorisation: 16×27×49 = 2⁴ × 3³ × 7² 8×27×125 = 2³ × 3³ × 5³ → hcf = 2³ × 3³ = 8×27 = 216


HCF by prime factorization by short division method?

1. HCF by factorisation Method: HCF is the product of common factors of all the numbers. Example: HCF of 24, 48, 60 First find the prime factors of these numbers 2 |24 2|48 2|60 24= 2*2*2*3 2|12 2|24 2|30 48= 2*2*2*2*3 2|6 2|12 3|15 60= 2*2*3*5 3|3 2|6 5|5 HCF= 2*2*3=12 |1 3|3 |1 |1 2. Division Method: Divide the larger number by the smaller number. Now divide the devisor by the remainder. Continue the process till the remainder is zero. Now this last devisor is the HCF of those two numbers. Repeat the process between this HCF and the other number. 48)60(1 48 12)48(4 48 0 12)60(5 60 0 Ans: 12


What are the factors of 10and 18?

10 = 2 x 5 18 = 2 x 3 x 3 HCF = 2 x 3 x 5 x 3 = 90