tn = n2
The given sequence is an arithmetic sequence where each term increases by 4. The first term (a) is 13, and the common difference (d) is 4. The nth term can be found using the formula: ( a_n = a + (n-1)d ). Therefore, the nth term is ( a_n = 13 + (n-1) \cdot 4 = 4n + 9 ).
The nth term is 7n-3 and so the next term will be 39
7n - 3
It is: 25-7n
The nth term is: 5-6n
Formula for nth termTn = a + (4n - 1) {where a is the first term and n is natural number}
25
It is 4n+5 and so the next term will be 25
tn = n2
Sn = 3n2 + 2n - 8
t(n) = 28-3n where n = 1,2,3,...
The nth term is 9n-2
As given, the sequence is too short to establish the generating rule. If the second term was 19 and NOT 29, then the nth term is tn = 6*n + 7 or 6(n+1)+1
The given sequence is an arithmetic sequence where each term increases by 4. The first term (a) is 13, and the common difference (d) is 4. The nth term can be found using the formula: ( a_n = a + (n-1)d ). Therefore, the nth term is ( a_n = 13 + (n-1) \cdot 4 = 4n + 9 ).
The nth term is 6n+1 and so the next term will be 31
The nth term is 7n-3 and so the next term will be 39