Depends upon what kind of assembly it is. There are dozens of different load factors to select from, not including exit load factors.
For instance, a dance hall of that size might accommodate 370 people (factor of 7 square feet per person), but only if the main entrance also provides for emergency exit of 245 of those people (2/3), meaning it would need to have 2 doors that were both 3 feet wide. There are many other factors, depending upon type of assembly, what floor it's on, etc.
That is 1000 x 2.6 x 1 = 2600 cubic feet. Sand weighs 100 pounds per cu ft, so it takes 100 x 2600 = 260,000 pounds, or 130 tons. Sand is deliverd by the cubic yard; that is about 100 yards of sand
How to dis-assemble the case
This question makes no sense. A 90 lb load per sq. ft. refers to an area. To calculate the stresses on beams supporting an area you have to know the spacing between adjacent beams as well as the span. p.s. This qn when fixed belongs in mechanical engineering.
That depends on the type of lighting . Fluorscent lighting for example , will give of little heat and fillament with generate far more .
It depends upon whether or not the wall is load bearing. If load bearing, the distance between standard studs is nominally 16 inches. If not load bearing, it can be 24 inches. There may be complications at the ends of the wall and doors and windows will also increase the number of 2x4's that are needed. A good rule of thumb is to figure one per foot. So in your case that would be 16.
It would depend almost entirely on what that room is USED for, i.e., the type of occupancy. If it is a storage room in a retail store, you are not allowed to have more than one person for each 300 sq ft (i.e., 5 people), but if it is a classroom in a K-12 education occupancy, you would be allowed one for each 20 sq ft of open space (net floorspace), i.e., 72 people. The NFPA Life Safety Code, or other similar code adopted in your jurisdiction, will determine what load factors to use for your particular occupancy, whatever it is. After you know the permissible load by area, you then calculate the permissible exit load, based upon the location, type and width of the various doors. If the exit load is smaller than the area load, your occupancy is limited by the exits.
It's the same as a room 1 ft wide, 2600 ft long.
Net floorspace divided by load factor from occupancy tables of applicable code. For instance, NFPA 101 requires 7 sq ft per person in compact dance areas and 15 sq ft per person where there is seating, provided it is not fixed seating. You then calculate the egress load by allowing one person for each 0.2 inches of doorway or hallway (whichever is narrower), or 0.3 inches if there are stairs. The lower number (area load or egress load) is the overall limit for that occupancy. There are, however, many other factors for each specific location, such as whether the main doors can accommodate at least 2/3 of the max load, whether there are sprinklers, whether there is live entertainment, what floor of the building it's on, what kind of building structure it is, etc.
2600 to 6700 ft
2600
68 ft x 40 ft
Assembly instructions for Pacific Casual 12.5 Ft X 9.5 Ft Oval Dome
Because there is not that much air like it is on the ground
That is 1000 x 2.6 x 1 = 2600 cubic feet. Sand weighs 100 pounds per cu ft, so it takes 100 x 2600 = 260,000 pounds, or 130 tons. Sand is deliverd by the cubic yard; that is about 100 yards of sand
Absolutely Not. Not enough detail to calculate load refer to NEC article 220 probably not, though
How many dole banana boxes in 20 ft container
Hub/bearing assembly to steering knuckle bolts, 77 ft lbs.Axle nut, 103 ft lbs.