Assuming the coin is fair, the probability of that sequence is 1/16.
The probability of three H and one T, in any order, is 1/4.
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Pr(3 flips at least one H) = 1 - Pr(3 flips, NO heads) = 1 - Pr(3 flips, TTT) = 1 - (1/2)3 = 1 - 1/8 = 7/8
The probability of getting two tails is 1/4. The probability of something happening is the answer to the question, "What fraction of the time will this happen?" It is the number of ways it can happen, out of all the different things that can happen. With two coin flips, these are all the things that can happen H H H T T H T T There is one way in which you can get two tails, out of four possible things that can happen. One out of four, or 1/4.
Two flips can have four possible results:T - TT - HH - TH - HThe question defines 'success' as either H-T or T-H.Two successes out of four possibilities = probability of 2/4 = 1/2 = 50% .
4: h/h, h/t, t/h & t/t
The sample space consists of all the possible outcomes. A flip of a coin has 2 outcomes, H,T. The total number of outcomes for 6 flips are 26 or 64.