The root of f(x)=(1-0.6x)/x is 1.6666...
To see how the bisection method is used please see the related question below (link).
(x + 2x + 3x) - 8 = 106x - 8 = 10Add 8 to each side:6x = 18Divide each side by 6:x = 3
6x + 7 < 3x + 106x - 3x
let accountants monthly income before raise in income be x then x + 6x\100 = 3460 106x/100 =3460 x = 3264.15 therefore accountants monthly income before raise was 3264.15
It is: 110x-2 simplified
Algebraically with X = numbers.X + (X + 1) = - 1052X + 1 = - 1052X = - 106X = - 53===========solution set
6x/2 = 106x = 10 x 2 (when taking the 2 to the RHS it is multiplied over because of the division on the LHS)6x = 20x = 20/6 (when taking the 6 to the RHS it id divided over because of the multiplication on the LHS)x = 4================================================================================Here, let me try:6x/2 = 10Reduce the fraction on the left to lowest terms.Divide numerator and denominator by 2:3x = 10Divide each side of the equation by 3:x = 10/3x = 31/3
(x + 2x + 3x) - 8 = 106x - 8 = 10Add 8 to each side:6x = 18Divide each side by 6:x = 3
6x + 7 < 3x + 106x - 3x
let accountants monthly income before raise in income be x then x + 6x\100 = 3460 106x/100 =3460 x = 3264.15 therefore accountants monthly income before raise was 3264.15
x + (x + 1) + (x + 2) + (x + 3) = 1424x + 6 = 142x = 3434 + 35 + 36 + 37 = 1425x+106x+157x+218x+289x+3610x+4511x+5512x+6613x+7814x+9115x+10516x+12017x+136There is only one sequence of consequent numbers that their sum is 142. Four consequent numbers.
To find the nth term of the sequence 104, 93, 82, 71, we need to determine the pattern or formula that governs the sequence. In this case, the sequence is decreasing by 11 each time. Therefore, the nth term can be expressed as 115 - 11n, where n represents the position of the term in the sequence.