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y = x2 + 16x - 4
The minimum value of y in this case is -b/2a, or -16/2, which is -8. If you solve the equation for x = -8, you will find the coordinates of the lowest point are (-8, -68).

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βˆ™ 15y ago
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Q: What is the absolute extrema of X2 plus 16X-4?
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