x2 = -11x - 10 x2 + 11x + 10 = 0 (x + 1)(x + 10) = 0
x2 -11x-12= (x-12)(x+1)
If you mean x2+11x+24 then it is (x+3)(x+8) when factored
x^3 - 121x
x2 + 11x + 18 (x + 9)(x + 2) CHECK: x2 + 9x + 2x + 18 x2 + 11x + 18 SET EACH EQUAL TO ZERO: x + 9 = 0 x = -9 x + 2 = 0 x = -2 NOW YOU ARE DONE: Solution set: {-9, -2}
x^3 - 121x
To solve for x: x2 = 11x - 10 x2 - 11x = -10 x2 - 11x + 10 =0 (x - 1)(x - 10) = 0 x = {1, 10)
x2 = -11x - 10 x2 + 11x + 10 = 0 (x + 1)(x + 10) = 0
x2 = 11x - 10 ∴ x2 - 11x + 10 = 0 ∴ (x - 10)(x - 1) = 0 ∴ x ∈ {1, 10}
x2 -11x-12= (x-12)(x+1)
X2 -11x +10=(x - 1 )(x - 10)
If you mean x2+11x+24 then it is (x+3)(x+8) when factored
21
-x2 - 11x + 26 = -(x2 + 11x - 26) = -(x2 - 2x + 13x - 26) = -[ x(x - 2) + 13(x - 2) ] = -(x + 13)(x - 2) = (x + 13)(2 - x)
Do you mean x2+11x-26 if so then it is (x-2)(x+13) when factored
Not possible to be specific since you have not provided the sign of the term in x, but there are two possible factorisations; (x + 3)(x + 8) = x2 + 11x + 24 and (x - 3)(x - 8) = x2 - 11x + 24
Assuming the question is written as: x2+11x-12 This would factor to: (x+12)(x-1)