0
Want this question answered?
Be notified when an answer is posted
Add your answer:
Earn +20 pts
What is formula to find sum of n even numbers?
There is no formula that will sum n even numbers without further qualifications: for example, n even numbers in a sequence.
Is the sum of two even numbers even or odd?
The sum of two even numbers is always EVENYes.Proof:We can consider an even number as 2*n, and an odd number as 2*n+1.The sum of two even numbers would be 2*n+2*m=2*(n+m), an even number.
Why is the sum of four consecutive numbers always even?
If n is the first number, n + n + 1 + n + 2 + n + 3 will be the sum, which is 4n + 6. 4n is always even, and 6 is even. Therefore, the sum of four consecutive numbers is always even.
Write the algorithm and draw the flowchart to find Sum of N Prime number?
Ah, finding the sum of N prime numbers is a lovely challenge! You can create an algorithm by first defining a function to check if a number is prime, then loop through numbers starting from 2 and add the prime numbers to a running sum until you reach N prime numbers. For the flowchart, you can start with a start/end symbol, then use decision symbols to check if a number is prime, loop symbols to iterate through numbers, and a process symbol to calculate the sum. Remember to add symbols for input and output as well. Happy algorithm painting!
What is the formula to find out the sum of first n even numbers?
n*(n+1)
Algorithm to find the sum of even numbers between 1 to 10?
sum = 0 for(n = 0; n <= 10; n += 2) sum += n;
What are the examples of algorithm in the flow chart?
TO find the sum of n numbers?
Write algorithm compute sum of square of N numbers?
Oh, what a lovely question! To compute the sum of the squares of N numbers, you can create a simple algorithm. Start by initializing a variable to hold the sum, then loop through each number, square it, and add it to the sum. Once you've done this for all N numbers, you'll have the sum of their squares. Just like painting a happy little tree, take your time and enjoy the process.
Write an algorithm find out the sum of first n odd numbers?
Algorithm: sum_evenInput: an integer, n, such that n>0Output: the sum of all even integers within the open range (1:n)sum := 0val := 2while (val < n) do{sum := sum + valval := val + 2}return sumNote that you explicitly specified between 1 and n, which literally means both 1 and n should be excluded from the sum. 1 would be excluded anyway since it is not an even number, however if we wish to include n, then use the following algorithm instead:Algorithm: sum_evenInput: an integer, n, such that n>0Output: the sum of all even integers within the half-open range (1:n]sum := 0val := 2while (val
How write algorithm for finding the sum first ten even number?
Sum = 0 For N = 1 to 10 Sum = Sum + 2*N Next N Print Sum
What is formula to find sum of n even numbers?
There is no formula that will sum n even numbers without further qualifications: for example, n even numbers in a sequence.
Algorithm to find the sum of even numbers between 1and 10?
1.start 2.n=1,s=0 3 compute s=s+n 4 compute n=n+1 5 check n<=10 go to step3 else go to step 7 6 display s 7 stop
Is the sum of two even numbers even or odd?
The sum of two even numbers is always EVENYes.Proof:We can consider an even number as 2*n, and an odd number as 2*n+1.The sum of two even numbers would be 2*n+2*m=2*(n+m), an even number.
Why is the sum of four consecutive numbers always even?
If n is the first number, n + n + 1 + n + 2 + n + 3 will be the sum, which is 4n + 6. 4n is always even, and 6 is even. Therefore, the sum of four consecutive numbers is always even.
What is the algorithm and flowchart to find Sum of natural numbers from 1 to10?
The general equation to find the sum of the numbers 1 to n is: (n*(n+1))/2So, for n=10, you have:(10*(10+1))/2(10*11)/2110/255
What is the formula to find sum of n even numbers?
Sum = n/2[2Xa1+(n-1)d] where n is last number, a1 is the first number & d is the common difference between the numbers, here d=2 for the even /odd numbers. Sum = n/2 [2Xa1+(n-1)2]
How would you find the sum of the first 50 even numbers?
Sum of 1st n even numbers: count*average = n * (2 + 2*n)/2 = n * (n+1) Sum = 50 * (2+100)/2 = 50*51 = 2550
