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Relative to the starting point, the coordinates of the end point are (10-7, 5) or (3, 5)

So the magnitude of the resultant vector is sqrt(32 + 52) = sqrt(9 + 25) = sqrt(34) = approx 5.83 km.

The bearing (measured from North) is arctan(3/5) = arctan(0.6) = 031 degrees.

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Q: What is the angle and the resultant vector of 10 km E and 5 km N and 7 km W?
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