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Factor this expression 4ac plus 2ad plus 2bc plus bd?
4ac + 2ad + 2bc +bd = 2a*(2c + d) + b*(2c + d) = (2c + d)*(2a + b)
Which of these formulas is correctly rewritten from the original formula to solve for b?
b = 1/2 (a - c) or for a = 3b - 2c: b = 1/3 (a + 2c) for a= 2bc + d is b= (a-d)/2c a= 2b +c is c= a - 2b b=1/3(a-2c)
What would the solution be if c-5d equals 2 and 2c plus d equals 4?
c - 5d = 2 2c + d = 4 Multiply eqn 1 by 2: 2c - 10d = 4 Subtract this from eqn 2: 0c + 11d = 0 which implies that d = 0 Then, by eqn 1, c = 2
Which of these formulas is correctly rewritten from a equals 2bc plus d to solve for b?
(a-d)/2c=b
Factor 4ac plus 2ad plus 2bc plus bd?
(2a + b)(2c + d)
Factor this expression 4ac plus 2ad plus 2bc plus bd?
4ac + 2ad + 2bc +bd = 2a*(2c + d) + b*(2c + d) = (2c + d)*(2a + b)
What is D Penny worth?
its worth 2c
Which of these formulas is correctly rewritten from the original formula to solve for b?
b = 1/2 (a - c) or for a = 3b - 2c: b = 1/3 (a + 2c) for a= 2bc + d is b= (a-d)/2c a= 2b +c is c= a - 2b b=1/3(a-2c)
What is 5d plus 2c in variables?
The expression is 5d+2c and the unknown variables are d and c
What would the solution be if c-5d equals 2 and 2c plus d equals 4?
c - 5d = 2 2c + d = 4 Multiply eqn 1 by 2: 2c - 10d = 4 Subtract this from eqn 2: 0c + 11d = 0 which implies that d = 0 Then, by eqn 1, c = 2
Which of these formulas is correctly rewritten from a equals 2bc plus d to solve for b?
(a-d)/2c=b
What is the answer to this ab - 2B plus ac -2C?
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What does 4ac 2ad 2bc bd factor into?
(2a + b)(2c + d)
How do you factor 3ab-3ad-2bc plus 2cd?
(3a - 2c)(b - d)
Factor 4ac plus 2ad plus 2bc plus bd?
(2a + b)(2c + d)
What is the factor to 4ac plus 2ad plus 2bc plus bd?
(2a + b)(2c + d)
How do you factor this expression 4ac plus 2ad plus 2bc plus bd?
(2a + b)(2c + d).
