x2 - 4x + 3 = 0 factors to (x - 1)(x - 3)
x = 1, 3
If you can't see this just by looking at it, recall the quadratic formula (remember this, it is so useful):-
The solutions for x of (ax^2 + bx + c = 0) are
( -b ± sqrt (b^2 - 4ac) ) / 2a
Try plugging in the values of a, b and c from the equation above, you will find the solutions for x.
0+3=3
3 + -3
3 + 0 = 3
(0, -3)
Zero
a = 3 and y = 0
x = 0
2x^2 + 8x + 3 = 0
x2 plus 3x plus 3 is equals to 0 can be solved by getting the roots.
(2x + 1)(x + 3) = 0; x = -0.5 or -3
(1, 0)
(-1, 0)